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mash [69]
2 years ago
9

Which expression is equivalent to StartFraction c squared minus 4 Over c + 3 EndFraction divided by StartFraction c + 2 Over 3 (

c squared minus 9) EndFraction
Mathematics
2 answers:
-Dominant- [34]2 years ago
5 0

The options have not been given but three correct alternatives have been presented as the solution.

Answer:

3(c-2)(c-3) or3(c^2-5c+6) or 3c^2 - 15c + 18

Step-by-step explanation:

\dfrac{c^2-4}{c+3}\div\dfrac{c+2}{3(c^2-9)}

Applying the rule a^2 - b^2 = (a+b)(a-b) to the numerator of the first term and the denominator of the second term,

\dfrac{c^2-2^2}{c+3}\div\dfrac{c+2}{3(c^2-3^2)}

\dfrac{(c+2)(c-2)}{c+3}\div\dfrac{c+2}{3(c+3)(c-3)}

By changing ÷ to ×, we invert the second term

\dfrac{(c+2)(c-2)}{c+3}\times\dfrac{3(c+3)(c-3)}{c+2}

(c-2)\times3(c-3)

3(c-2)(c-3) = 3(c^2-5c+6) = 3c^2 - 15c + 18

Yakvenalex [24]2 years ago
4 0

Answer:

The answer is C on edge

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The word geometry has eight letters. three letters are chosen at random. what is the probability that two consonants and one vow
olga nikolaevna [1]

Answer:

0.536 is the required probability.

Step-by-step explanation:

 We have been given the word the word "GEOMETRY"

we have to find the probability that two consonants and one vowel are chosen:

Number of consonants are: 5

Number of  vowels are: 3

Hence, The required probability is: \frac{^5C_2\cdot ^3C_1}{^8C_3}

Using: ^nC_r=\frac{n!}{(r!)(n-r)!}

\frac{\frac{5!}{3!\cdot 2!}\cdot\frac{3!}{1!\cdot 2!}}{\frac{8!}{3!\cdot 5!}}

Simplifying the above expression:

\frac{\frac{5\cdot 4\cdot 3!}{3!\cdot 2}\cdot {\frac{3\cdot 2!}{2!}}}{\frac{8\cdot 7\cdot 6\cdot 5!}{5!\cdot 3\cdot 2}}

Further simplification after cancelling out the common terms we get:

\Rightarrow \frac{30}{56}=\frac{15}{28}=0.5357=0.536

Hence, Option 1 is correct.


4 0
2 years ago
Read 2 more answers
PLEASE HELP!!!!!!
jek_recluse [69]
\bf \textit{Law of Cosines}\\ \quad \\
c^2 = {{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)\implies 
c = \sqrt{{{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)}\\\\
-----------------------------\\\\

\begin{cases}
a=12\\
b=10\\
D=90+50
\end{cases}\implies d = \sqrt{{{ 12}}^2+{{ 10}}^2-2(12)(10)cos(140^o)}
\\\\\\
d\approx \sqrt{427.851}\implies d\approx 20.684551
5 0
2 years ago
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A student scored in the 85th percentile on her chemistry exam. What does this student's score mean in relation to those of the o
Trava [24]

Answer:

The answer is  

her score was in the top 85% of all test takers' scores.

Step-by-step explanation:

Percentile is the relative standing in a set of data from the lowest values to highest values.

If your score is in the 85th percentile, it means that 85% of the scores are below your score and 15% are above your score.

7 0
2 years ago
Old faithful in Yellowstone National Park shoots water 60 feet into the air that casts a shadow of 42 feet. What is the height o
Serhud [2]

Answer:

The height of near by tree will be 90 feet.

Step-by-step explanation:

Considering the water triangle as shown in figure a.

As the old faithful shoots water 60 feet into the air that casts a shadow of 42 feet.

Considering the tree triangle as shown in figure a. The tree triangle has a shadow 63 feet long.

Let x be the height of near by tree that cost a shadow 63 feet long.

Assuming that the triangles are similar

So,

the ratios of similar triangles will be related as:

\frac{63}{42}=\frac{x}{60}

\mathrm{Switch\:sides}

\frac{x}{60}=\frac{63}{42}

{x}=60.\frac{63}{42}

x=90 feet

Therefore, the height of near by tree will be 90 feet.

Keywords: ratio, similar triangle

Learn more about similar triangle from brainly.com/question/10161974

#learnwithBrainly

7 0
2 years ago
Alice and Briana each participate in a 5 kilometer race. Alice's distance covered, in kilometers, after t minutes can be modeled
Pavel [41]

Answer:

a. Alice

b. Briana

c. 0.51 minutes

Step-by-step explanation:

a. Alice formula is valid for any t > 0 minutes, but Briana formula is only valid for

2t - 1 > 0

2t > 1

t > 1/2 minutes

b. They finish when their covered distance is equal to 5 kilometers. For Alice:

t/4 = 5

t = 5*4 = 20 minutes

For Briana:

√(2t - 1) = 5

2t - 1 = 5²

2t = 25 + 1

t = 26/2

t = 13 minutes

c. They are side by side when they have covered the same distance, that is:

t/4 = √(2t - 1)

(t/4)² = 2t - 1

t²/16 = 2t - 1

t² = 16*(2t - 1)

t² = 32t - 16

t² - 32t + 16 = 0

Using quadratic formula:

t = \frac{-b \pm \sqrt{b^2 - 4(a)(c)}}{2(a)}

t = \frac{32 \pm \sqrt{-32^2 - 4(1)(16)}}{2(1)}

t = \frac{32 \pm 30.98}{2}

t_1 = \frac{32 + 30.98}{2}

t_1 = 31.49

t_2 = \frac{32 - 30.98}{2}

t_2 = 0.51

Only the second answer has sense for this problem because the race already finished before they spent 31.49 minutes in it.

4 0
2 years ago
Read 2 more answers
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