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melomori [17]
2 years ago
11

Find the values for a, b, and c that complete the simplification.

Mathematics
1 answer:
lisov135 [29]2 years ago
8 0

Answer: A: 6

B: 4

C: 2

Step-by-step explanation:

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A school principal has to choose randomly among the six best students in each grade to be the school captain every month. For th
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Since there are 6 students out of which one needs to be selected, the principal chose two die on which there are six numbers each numbered from 1 , 2, 3, 4, 5, 6.

Since there are two dice, the total possible outcome is 36.

Hence, the probability of getting one number each is 1/36

Hence, the principal used a fair method because each result is an equally likely possible outcome.

Option B is correct.

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Find the third degree polynomial function that has an output of 1,025 when x=5, and has zeros −20 and −4i.
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im not sure

Step-by-step explanation:

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Lenny sold 576 tacos in 48 hours what was lenny's average rate of tacos sales
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If your looking for hourly they sold a total of 12 tacos per hour.
If your looking for daily they sold a total of 288 tacos per day.
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If m∠1 = 50, then m∠5 =
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1. angle 1 = 50 degrees [ Reason is Given]
2. angle 1 and angle 5 are corresponding angles [Given]
3..Therefore angle1=angle 5 [ Corresponding angles are =]
4..Therefore angle 5 = 50 degrees [= angles have same measure]

The above assumes that we are talking about corresponding angles of congruent or similar polygons or corresponding angles forme when a transversal intersects two parallel lines
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2 years ago
32​% of U.S. adults say they are more likely to make purchases during a sales tax holiday. You randomly select 10 adults. Find t
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Answer:

A.  21.06%

B. 66.88%

C. 81.56%

Step-by-step explanation:

There are two possible answer for the question asked, yes(more likely to make purchases) or no. The probability for a random adults answer yes to the question is 32% so the probability that the adults answer no is 68%.

(a) exactly​ two

There is only one case for this question, 2 people say yes and 8 people say no. The calculation for this problem will be:

2P10 * P(yes)^2 * P(no)^8= 10!/2!8!* 32%^2  * 68%^8 = 0.21066= 21.06%

(b) more than​ two

There are a lot of case for more than two, its easier to find out the negation of the probability which is "two or less". Case that fulfill "two or less" will be: 2 yes and 8 no

1 yes and 9 no

0 yes and 10 no

The calculation for the negation will be:

~P(X)= 0P10 * P(yes)^0 * P(no)^10   +   1P10 * P(yes)^1 * P(no)^9   +  2P10 * P(yes)^2 * P(no)^8  =

10!/0!10!* 32%^0  * 68%^10    +   10!/1!9!* 32%^1  * 68%^9   +   10!/2!8!* 32%^2  * 68%^8

0.02113 + 0.09947 + 0.21066  =  0.33126= 33.12%

Since its the negation, you need to subtract 1 with the negation

P(X)= 1 - ~P(X)

P(X)= 1 - 33.12%= 66.88%

(c) between two and​ five, inclusive

Same formula as above, but the case is:

2 yes and 8 no

3 yes and 7 no

4 yes and 6 no

5 yes and 5 no

The calculation will be:

2P10 * P(yes)^2 * P(no)^8 + 3P10 * P(yes)^3 * P(no)^7 + 4P10 * P(yes)^4 * P(no)^6 + 5P10 * P(yes)^5 * P(no)^5 =

10!/2!8!* 32%^2  * 68%^8    +   10!/3!7!* 32%^3  * 68%^7   +   10!/4!6!* 32%^4  * 68%^6  +  10!/5!5!* 32%^5  * 68%^5

0.21066 + 0.26435 + 0.21770 + 0.1229= 0.81561= 81.56%

8 0
2 years ago
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