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dangina [55]
2 years ago
11

jason runs 440 yards in 75 seconds.At this rate how many minutes does it take him to run a mile? (1 mile = 1,760 yards)​

Mathematics
1 answer:
Zepler [3.9K]2 years ago
7 0

Answer: 5 minutes

Step-by-step explanation:

We know that 1760 yards are in a mile. We can convert the given info into a proportion. 440/75 = 1760/x, where x is the number of seconds it takes to run a mile. Cross-multiply to get 440x = 75*1760. Divide both sides by 440 to get x = 75*4 = 300 seconds. The problem asks for how many minutes so you have to convert 300 seconds to minutes. To do this, we have to divide 300 by 60 to get 5 minutes.

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Chang knows one side of a triangle is 13 cm. Which set of two sides is possible for the lengths of the other two sides
cestrela7 [59]

Answer:

Choice D - 8cm and 9cm.

Step-by-step explanation:

The other sides are not greater than 13.

A: 5 + 8 = 13

B: 6 + 7 = 13

C: 7 + 2 = 9

However, <u>D is greater than 13 and is the correct answer.</u>

D: 8 + 8 = 16.

3 0
2 years ago
The dimensions of a right rectangular prism are 2 m, 2.5 m, and 4.5 m.
Kisachek [45]

Answer:

volume= length ×width×height

2×2.5×4.5

22.5

3 0
2 years ago
A parallelogram with sides of 6 and 10 has an area of 30. Find the measure of the small angle of the parallelogram.
dmitriy555 [2]
<span>A = 2 * (0.5ab) + b (10 - a) = ab + 10b - ab = 10b 

10b = 30√2; b = 3√2 

sin α = 3√2 / 6; α = 45 degrees 

Small angle: 45°; Large angle: 135°</span><span>
</span>
4 0
2 years ago
Two boats leave port at noon. Boat 1 sails due east at 12 knots. Boat 2 sails due south at 8 knots. At 2 pm the wind diminishes
Ivan

Answer:

14.86 knots.

Step-by-step explanation:

<em>Given that:</em>

The boats leave the port at noon.

Speed of boat 1 = 12 knots due east

Speed of boat 2 = 8 knots due south

At 2 pm:

Distance traveled by boat 1 = 24 units due east

Distance traveled by boat 2 = 16 units due south

Now, speed of boat 1 changes to 9 knots:

At 3 pm:

Distance traveled by boat 1 = 24 + 9= 33 units due east

Distance traveled by boat 2 = 16+8 = 24 units due south

Now, speed of boat 1 changes to 8+7 = 15 knots

At 5 pm:

Distance traveled by boat 1 = 33 + 2\times 9= 51 units due east

Distance traveled by boat 2 = 24 + 2 \times 15 = 54 units due south

Now, the situation of distance traveled can be seen by the attached right angled \triangle AOB.

O is the port and A is the location of boat 1

B is the location of boat 2.

Using pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^{2} = 51^{2} + 54^{2}\\\Rightarrow AB^{2} = 2601+ 2916 = 5517\\\Rightarrow AB = 74.28\ units

so, the total distance between the two boats is 74.28 units.

Change in distance per hour = \dfrac{Total\ distance}{Total\ time}

\Rightarrow \dfrac{74.28}{5} = 14.86\ knots

6 0
2 years ago
Suppose c and d vary inversely, and d = 2 when c = 17.
balu736 [363]

Answer:

c = 34/d

d = 1/2

Step-by-step explanation:

Part A

Basic Formula

c = k/d

17 = k/2         Multiply both sides by 2

17*2 = k*2/2     Combine

34 = k

So the equation is c = 34/d

Part B

c = 68

k = 34

d = ?

68 = 34/d               Multiply both sides by d

68*d = 34 * d/d      Simplify.

68 d = 34                Divide by 68

d = 34/68                Simplify

d = 1/2

5 0
2 years ago
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