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2 years ago

Use the diagram to complete the statement.

Mathematics

2 answers:

erica [24]2 years ago

8 0

we know that

in the right triangle JKL

$sin(38\°)=cos(52\°)$

Because

$(38\°)$ and $(52\°)$ are complementary angles

$38\°+52\°=90\°$

therefore

<u>the answer is</u>

$cos(52\°)$

yanalaym [24]2 years ago

4 0

I hope this helps you

sin38=cos52

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You didn't write the equation you like to be solved. It is clear though, from the options you gave, that there are two equations you want to be solved simultaneously. I will give an example to illustrate this, and you may apply the process in solving your problem.

Step-by-step explanation:

Let

x + y = 7 ....................................(1)

x - 2y = -2...................................(2)

SOLVING USING THE SUBSTITUTION METHOD.

From (1), make y the subject.

y = 7 - x ....................................(3)

Substitute the value of y in (3) into (2)

x - 2(7 - x) = -2

x - 14 + 2x = -2

x + 2x = -2 + 14

3x = 12

Divide both sides by 3

x = 12/3 = 4

Now use x = 4 in (3)

y = 7 - 4 = 3

Therefore, ( x, y) = (4, 3)

SOLVING USING THE ELIMINATION METHOD.

x + y = 7 ....................................(1)

x - 2y = -2...................................(2)

First, let us eliminate x by subtracting (2) from (1)

(x + y) - (x - 2y) = 7 - (-2)

y + 2y = 7 + 2

3y = 9

Divide both sides by 3

y = 9/3 = 3

To eliminate y, first multiply (1) by 2, and add the result to (1)

2 × (1): 2x + 2y = 14 ........................(3)

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____________________

...............3x = 12

............... x = 12/3 = 4

Therefore (x, y) = (4, 3)

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