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Ivahew [28]
2 years ago
9

A manufacturer of cheese filled ravioli supplies a pizza restaurant chain. Based on data collected from its automatic filling​ p

rocess, the amount of cheese inserted into the ravioli is normally distributed. To make sure that the automatic filling process is on​ target, quality control inspectors take a random sample of 25 ravioli and measure the weight of cheese filling. They find a sample mean weight of 15 grams with a standard deviation of 1.5 grams. What is the margin of error at​ 90% confidence?
Mathematics
1 answer:
docker41 [41]2 years ago
6 0

Answer:

The margin of error at 90% confidence is 0.5133 gram.

Step-by-step explanation:

Margin of error (E) = (critical value × sample standard deviation) ÷ sqrt(n)

sample standard deviation = 1.5 grams

confidence level = 90% = 0.9

significance level = 1 - C = 1 - 0.9 = 0.1 = 10%

n (sample size) = 25

degree of freedom = n - 1 = 25 - 1 = 24

critical value (t) corresponding to 24 degrees of freedom and 10% significance level is 1.711

E = (1.711×1.5) ÷ sqrt(25) = 2.5665 ÷ 5 = 0.5133 gram

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Answer:

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Explanation:

The place-value chart is:

Hundreds         Tens      Ones

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<em><u>a)  Between which two tens does it fall? </u></em>

Using the place values you can write 253 = 25 × 10 + 3, i.e. 25 tens and 3 ones.

From that you can write:

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Then, you conclude that 253 is between 25 and 26 tens.

<u><em>b) Between which two hundreds does it fall?</em></u>

Using the same reasoning:

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Conclusion: 253 is between 2 hundreds and 3 hundreds.

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