Answer:
p₁ - p₂ = ( -0,28 . 0 )
Step-by-step explanation:
Eastern gray squirrel
Sample size n₁ = 60
p₁ = 22 % p₁ = 0,22 then q₁ = 1 - 0,22 q₁ = 0,88
Western gray squirrel
Sample size n₂ = 120
p₂ = 36% p₂ = 0,36 Then q₂ = 1 - 0,36 q₂ = 0,64
p (s) = ( p₁ - p₂ ) /√ (p₁*q₁ ) / n₁ + (p₂*q₂/ n₂)
p(s) = ( 0,22 - 0,36 ) /√ (0,22*0,88)/60 + ( 0,36*0,64)/120
p(s) = -0,14 /0,071
p(s) = - 1,9718
Then
CI = ( p₁ - p₂ ) ± p(s) *EED
EED = /√ (p₁*q₁ ) / n₁ + (p₂*q₂/ n₂) = 0,071
CI = ( - 0,14 ± 1,9718 * 0,071 )
CI = ( - 0,14 ± 0,14 )
CI = ( - 0,28 ; 0 )
we will find with 95% of confidence the mean of the sampling distribution of the difference in sample proportion in the interval ( -0,28 , 0 )
p₁ - p₂ = ( -0,28 . 0 )
