Answer:
The probability that they are both male is 0.424 (3 d.p.)
Step-by-step explanation:
The first step is to find the probability of the first selection being male. This is calculated as number of male mice divided by total number of mice in the litter
Prob (1st male) = 8 ÷ 12 = 0.667
Next is to find the probability of the second selection also being male. Note that the question states that the first mice was selected without replacement. This means the first mouse taken results in a reduction in both the number of male mice and total number of mice in the litter.
Prob (2nd male) = (8 - 1) ÷ (12 - 1) = 7/11 = 0.636
Therefore,
Prob (1st male & 2nd male) = 0.667 × 0.636 = 0.424
Answer:
(13/10)H
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Remember that 30% in fraction form is 33/100
The amount of health points (H) restored would depend on the amount of the current H so it means it would add 30% of the current which we can write as:
(30/100)H
And since it would add that to the current total we can right the current total as:
(100/100)H
So our equation would be
=(30/100)H + (100/100)H
=(130/100)H
=(13/10)H