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Mademuasel [1]
2 years ago
9

Ravi is running against two other candidates for student council president. All of the 750 students in Ravi's school will vote f

or student council president. How can Ravi generate a representative sample that will help him determine whether he will win the election?​
Mathematics
1 answer:
julsineya [31]2 years ago
3 0

Answer:

50 students from each grade

Step-by-step explanation:

getting the same amount of people from each grade would show you about the percentage frome each grade which would give about how many people would vote per grade and show about how many would vote school wide

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this month drew worked six hours less than twice the number of hours H he worked last month. what expression represents the numb
Klio2033 [76]

Answer:

2x-6

Step-by-step explanation:

I think, I might be wrong

5 0
2 years ago
Read 2 more answers
The packaging lists a model airplane’s length as 10.5 in. It also gives the scale as 1:83. What is the length of the actual airp
Lana71 [14]
\bf \cfrac{\stackrel{model}{length}}{\stackrel{actual}{length}}\qquad 1:83\qquad \cfrac{1}{83}\implies \cfrac{1}{83}=\cfrac{10.5}{x}\implies x=\cfrac{83\cdot 10.5}{1}
\\\\\\
x=871.5~inches
\\\\\\
\textit{there are 12 inches in 1 foot, thus }
\\\\\\
871.5~\underline{in}\cdot \cfrac{ft}{12~\underline{in}}\implies 72.625~ft 
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6 0
2 years ago
Ne Friday night, a group of friends bought 5 containers of popcorn and 4 granola bars at the movie theatre for $42.50. The next
Tomtit [17]

In this question , it is given that p represents cost of 1 container of popcorn . Therefore cost of 5 containers of popcorn = 5p and cost of 3 containers of popcorn = 3p .

And g represents cost of 1 container of granola bars. THerefore cost of 4 containers of granola bars = 4g and cost of 6 containers of granola bars = 6g .

According to the given question, the required linear equations are

5p+4g=42.50 , 3p+6g =34.50 .

And these are the the required system of linear equation .

4 0
2 years ago
Line JM intersects line GK at point N. Which statements are true about the figure? Check all that apply.
ki77a [65]
See attached image

First, we must know this: Complementary angles are two angles whose sum is equal to 90°, while supplementary angles are two angles whose sum is equal to 180°. That been said, the only statement which is true is the second statement, <span>MNL is complementary to KNL

Reasons why others are False
</span>GNJ is supplementary to JNK, not complementary
MNG is supplementary to GNJ, not complementary
LNJ (not KNJ) <span>is supplementary to MNL
</span>GNM is equal to JNK, not supplementary

8 0
2 years ago
Read 2 more answers
A bin of 5 transistors is known to contain 2 that are defective. The transistors are to be tested, one at a time, until the defe
xxMikexx [17]

Answer:

P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}

Step-by-step explanation:

For the random variable N_1 we define the possible values for this variable on this case [1,2,3,4,5] . We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:

5C2 = \frac{5!}{2! (5-2)!}= \frac{5*4*3!}{2! 3!}= \frac{5*4}{2*1}=10

We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable N_1 like this:

P(N_1 = a) = \frac{5-a C 1}{5C2}

For the distribution of N_2 we need to take in count that we are finding a conditional distribution. N_2 given N_1 =a, for this case we see that N_2 \in [1,2,...,5-a], so then exist 5-a C 1 ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:

P(N_2 =b | N_1 = a) = \frac{1}{5-a C 1}

And if we want to find the joint probability we just need to do this:

P(N_1 = a , N_2 = b) = P(N_2 = b | N_1 = a) P(N_1 =a)

And if we multiply the probabilities founded we got:

P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}

8 0
2 years ago
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