Michael is constructing a circle circumscribed about a triangle. He has partially completed the construction. What should be his
2 answers:
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Answer:
4.979044478499338 × 10²⁶
Step-by-step explanation:
Combination can be used to determine the number of ways the mice can be selected for the drugs (A, B) and the control group.
Combination factorial is define by ⁿCr =
21 group of mice receiving Drug A can be selected in ⁶⁰C₂₁ =
(60 - 21 = 39 ) mice remained for selection of 21 mice for the second drug
Drug B 21 mice can be chosen with ³⁹C₂₁ =
( 39 - 21 = 18) remained for control with ¹⁸C₁₈ =
The number of ways the mice can be chosen for drug A, drug B and the control = ⁶⁰C₂₁ × ³⁹C₂₁ × ¹⁸C₁₈ = ×
×
= 4.979044478499338 × 10²⁶
Answer:
Step-by-step explanation:
Hello!
You have the variable
X: Area that can be painted with a can of spray paint (feet²)
The variable has a normal distribution with mean μ= 25 feet² and standard deviation δ= 3 feet²
since the variable has a normal distribution, you have to convert it to standard normal distribution to be able to use the tabulated accumulated probabilities.
a.
P(X>27)
First step is to standardize the value of X using Z= (X-μ)/ δ ~N(0;1)
P(Z>(27-25)/3)
P(Z>0.67)
Now that you have the corresponding Z value you can look for it in the table, but since tha table has probabilities of , you have to do the following conervertion:
P(Z>0.67)= 1 - P(Z≤0.67)= 1 - 0.74857= 0.25143
b.
There was a sample of 20 cans taken and you need to calculate the probability of painting on average an area of 540 feet².
The sample mean has the same distribution as the variable it is ariginated from, but it's variability is affected by the sample size, so it has a normal distribution with parameners:
X[bar]~N(μ;δ²/n)
So the Z you have to use to standardize the value of the sample mean is Z=(X[bar]-μ)/(δ/√n)~N(0;1)
To paint 540 feet² using 20 cans you have to paint around 540/20= 27 feet² per can.
c.
P(X≤27) = P(Z≤(27-25)/(3/√20))= P(Z≤2.98)= 0.999
d.
No. If the distribution is skewed and not normal, you cannot use the normal distribution to calculate the probabilities. You could use the central limit theorem to approximate the sampling distribution to normal if the sample size was 30 or grater but this is not the case.
I hope it helps!
Answer: THE GRAPH IS ATTACHED.
Step-by-step explanation:
We know that the lines are:
Solving for "y" from the first line, we get:
In order to graph them, we can find the x-intercepts and the y-intercepts.
For the line the x-intercepts is:
And the y-intercept is:
For the line the x-intercepts is:
And the y-intercept is:
Now we can graph both lines, as you can observe in the image attached (The symbols and
indicates that the lines must be dashed).
By definition, the solution is the intersection region of all the solutions in the system of inequalities.
