(12 - 9) / 12 = (40 - x) / 40
3/12 = (40 - x) / 40
40(1/4) = 40 - x
10 = 40 - x
10 - 40 = -x
-30 = -x
30 = x <=== percent decrease from 40 to 30
for the rectangular red paper :
w₁ = width of the red paper = 4 cm
L₁ = length of red paper = 2 w = 2 x 4 = 8 cm
A₁ = area of the red paper = L₁ w₁ = 8 x 4 = 32 cm²
for the rectangular blue paper :
w₂ = width of the blue paper = 3 cm
L₂ = length of blue paper = 7 cm
A₂ = area of the blue paper = L₂ w₂ = 7 x 3 = 21 cm²
area visible is given as
A = A₁ - A₂ = 32 cm² - 21 cm² = 11 cm²
so 11 square units of red paper will be visible on top
Answer:
<em>5,598 cans are required to empty the vessel</em>
Step-by-step explanation:
The volume of a cylinder of radius r and height h is:

The volume of a box of dimensions X, Y, and Z is:
V=X.Y.Z
A cylinder of r=1.4 m and height h=1.5 is used to store vegetable ghee. It contains a volume of:


Converting to cubic cm:


The volume of each rectangular tin can is:


The number of cans required to empty the vessel is:

5,598 cans are required to empty the vessel