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dlinn [17]
2 years ago
9

Consumers will bear switching costs if: a. the benefits of adopting the new technology outweigh the costs of switching. b. switc

hing costs are substantial. c. the new products are packaged attractively. d. there is a lack of complementary products. e. the new technology is advertised subtly.
Business
1 answer:
Katarina [22]2 years ago
3 0

Answer: a. the benefits of adopting the new technology outweigh the costs of switching.

Explanation: Switching costs are defined as those cost the consumer pays as the result of changing brands or products, but can also be manifested in the form of time and effort spent during the switching process, the risk of disruption of business operations during the period of switching etc. and so therefore, switching costs can be monetary, psychological, effort-based, or time-based.

Companies with difficult-to-master products and low competition often times will use high switching costs to maximize profit by typically employing strategies that incur high switching costs on the consumer. Therefore, consumers will bear the costs of switching if the benefits of adopting the new technology outweigh the costs of switching.

You might be interested in
Your uncle holds just one stock, East Coast Bank (ECB). You agree that this stock is relatively safe, but you want to demonstrat
g100num [7]

Complete question:

Assume that your uncle holds just one stock, East Coast Bank (ECB), which he thinks has very little risk.  You agree that the stock is relatively safe, but you want to demonstrate that his risk would be even lower if he were more diversified.  You obtain the following returns data for West Coast Bank (WCB).  Both banks have had less variability than most other stocks over the past 5 years.  

                   Year               ECB                WCB  

               2004             40.00%            40.00%

               2005            -10.00%            15.00%

               2006             35.00%            -5.00%

               2007             -5.00%           -10.00%

               2008             15.00%            35.00%

a. What is the expected return and risk of each stock?

b. Measured by the standard deviation of returns, by how much would your uncle's risk have been reduced if he had held a portfolio consisting of 60% in ECB and the remainder in WCB?  In other words, what is the difference between portfolio's standard deviation and weighted average of components' standard deviations? (Hint: check the example on page 11-12 on my note).

Solution:

The estimated return of the stock is the average profit.

So the average of ECB is (40-10+35-5+15)/5

=  \frac{75 percent}{5}

= 15% expected return

WCB expected return = 40+15-5-10+35  

= \frac{75 percent}{5}

= 15%

They've had the same planned return.

This is generally defined in the Greek letter Mu, (U) A weighted average may also be used to calculate portfolio volatility.

Standard deviation of ECB is \sqrt{{ sum [(x-U)^2]/5}}

so for ECB:

(40-15)^2= 25^2 =6.25%

(-10-15)^2= -35^2 = 0.1225

(35-15)^2= 20^2 = 0.04

(-5-15)^2= -20^2 = 0.04

(15-15)^2=0

now 0.0625+0.1225+0.04+0.04+0=0.265

stdev= \sqrt{(0.265/5)} = 0.23

So WCB is the same except in a different order to make things quick I'm only going to add the median again WCB=0.23

Then the 60/40 portfolio will be the "weighted average" of the returns.

portfolio returns

2004: (60%*40%)+(40%*40%) = 40%

2005: (60%*-10%)+(40%*15%) = 0%

2006: (60%*35%)+(40%*-5%) = 19%

2007: (60%*-5%)+(40%*-10%) = -7%

2008:(60%*15%)+(40%*35%) = 23%

we have an average return of (40+19-7+23)/5 = 75/5 =15%  

The estimated return of all combined stocks is a better way to do so.

we knew they both had expected returns of 15% so we can say  

(60%*15%)+(40%*15%)=15%  so the portfolio has an expected return of 15%

Now we do the standard deviation for the whole portfolio and get

(40-15)^2= 25^2 =6.25%

(0-15)^2 = - 25^2 =6.25%

(19-15)^2= 4^2 = 0.16%

(-7-15)^2 = -22^2 = -4.84%

(23-15)^2= 8^2 = 0.64%

now add them up and get 9.78%

\sqrt{(9.78%/5)} = 13.98%

Therefore, the normal portfolio variance is 13.98 per cent and the predicted portfolio return is 15 per cent.

Every stock has a standard deviation of 23 per cent and an average return of 15 per cent, meaning that the fund has the same estimated return but with less standard deviation. This ensures that the same gain is less costly. It's stronger than any of these products.

5 0
1 year ago
The demand for flip phones has drastically reduced, and there are only a few consumer electronics companies selling them at extr
lidiya [134]

Answer:

<u>Laggards are in the late 16 % of the cycle of adoption of the technology.</u>

Explanation:

  • As technology adoption is a sociological model that is based on the acceptance of the newer product or innovation that defines the demographic characteristics.
  • Innovators, early adopters, early majority and late majority and laggards are all the demographic and psychological group of people that adopt the model based on the consideration as the flip phone are rarely available and they tend to have lower demands in the market hence only fewer companies keep those models.
  • Even though selling them at a lower price they are taken up by laggards as these are ones that usually take the flip phones based on their perception and the trends in the market.
8 0
1 year ago
Read 2 more answers
A major lottery advertises that it pays the winner $10 million. However, this prize money is paid at the rate of $ 500,000 each
My name is Ann [436]

Answer:

We have to discount these payments to find the present value

500,000

500,000/1.1

500,000/1.1^2

500,000/1.1^3

We keep on doing this until we reach 500,000/1.1^19

After that we add all the payments and get the value. A less time consuming way of doing it is using a financial calculator

Pv=?

N=19

FV=0

PMT=500,000

=4,182,460.05 we add 500,000 to this because the first payment was not discounted=4,682,460.05= Present Value.

Explanation:

8 0
1 year ago
A company is selling bonds with a face value of $1,000 to raise money for a plant expansion. The bonds pay a coupon rate of 4% p
Ksivusya [100]

Answer:

10.26%

Explanation:

According to the scenario, computation of the given data are as follow:-

Net sales = $760

Face value of bonds = $1,000

Coupon rate = 4% = $1,000 × 4 ÷ 100

= 40

N = Number of Years = 5 annually = semiannually = 5 × 2

= 10 years

We assume, interest rate = 10% = 0.10

P = Coupon Rate ÷ 2 × (PVIFA,Interest Rate ÷ 2%,No. of Years) + Future Value(PVIF,Interest Rate ÷ 2%, No. of Years)

=$40 ÷ 2 × [1 - 1 ÷ (1 + Interest Rate)N] ÷ Interest Rate + Future Value[1 ÷ (1 + Interest Rate) × N]

=$40 ÷ 2 × [1-1 ÷ (1 + 0.10 ÷ 2)^10] ÷ 0.05 + $1,000 × [1 ÷ (1 + 0.10 ÷ 2)^10]

=$20 × [1 - 1 ÷ (1.05)^10] ÷ 0.05 + $1,000 × [1 ÷ (1.05)^10]

=$20 × [1 -1 ÷ 1.6288946] ÷ 0.05 + $1,000 × [1 ÷ 1.6288946]

= 420 × 7.72173 + $1,000 × 0.613913

= $154.4346 + $613.913

= $768.3476

= $768.35

But the given value is 760, so we assume interest rate = 11%

=$40 ÷ 2 × [1-1 ÷ (1 + Interest Rate)^N] ÷ Interest Rate + Future Value[1 ÷ (1 + Interest Rate)^N]

= $40 ÷ 2 × [1 - 1 ÷(1 + 0.11 ÷ 2)^10] ÷ 0.055 + $1,000 × [1 ÷ (1 + 0.11 ÷ 2)^10]

= $20 × [1 - 1 ÷ (1.055)^10] ÷ 0.055 + $1,000 × [1 ÷ (1.055)^10]

= $20 × [1 - 1 ÷ 1.70814446] ÷ 0.055 + $1000 × [1 ÷ 1.70814446]

= $20 × 7.5376255 + $1,000 × 0.5854306

= $150.75 + $585.43

= $736.18

At the Interest rate of 10% the price is more than $760 and at the Interest rate of 1% the price is less than $760. So the required rate lies in between 10% to 11%.

So required rate  

Yield To Maturity = Lower Interest Rate + (Difference Between Interest Rate) × Higher Price - Received Price ÷ Higher Price - Lower Price

= 1 0+( 11 - 10) × $768.35 - $760 ÷ $768.35 - $736.18

= 10 + 1 × $8.35 ÷ $32.17

= 10 + 0.26

= 10.26%

7 0
1 year ago
An upset forging plant will be built to produce 2,000,000 parts per year. The plant will operate for three 8-hour shifts per day
miv72 [106K]

Answer:

A. 16

B. 57.14

Explanation:

forging presses = 20

setup time = 3 hours

Time required to produce 1 batch = 600 *45 s = 7.5 hours

total workforce = 7 in all;

a. no of forged parts produced in a month ;

total time required to produce 1 forged part = 3 + 7.5 = 10.5 hours;

working hours a day = 8 ;

total no of working days = 21/month;

total no of batches produced n= 21*8/10.5;

n = 16;

so no of parts = 16 * 600 = 9600;

b. labor productivity P= parts /work hour;

P = 9600/21*8 = 57.14

3 0
2 years ago
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