Consider two flat plate airfoils as lumped "lifting elements" in a tandem arrangement, where the second airfoil is located at so
me distance downstream from the first airfoil. The chords and attack angles of both airfoils are the same. Find the circulations of these airfoils in terms of the free-stream velocity U , attack angle , chord c , and the distance between the airfoils’ leading edges d . Which airfoil generates higher lift force and why? Discuss the effect of the distance between the airfoils on their aerodynamic interaction.
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Answer:
The camera would flow the same velocity and acceleration of the droplet until 9ft. After that it would switch gear and accelerate back to its original spot at the rate of 140.54 m/s2 in order to catch the next droplet.
Explanation:
The time it takes for the drop to reach 7-ft and 9-ft at the acceleration of 32.2ft/s2:
When s = 7ft,
When s = 9ft,
So it would take Δt = 0.75 - 0.66 = 0.09 s for each drop to travel from 7ft to 9ft. As the drops are released every 0.5s, this means that after our cam follow the first drop to the end of the 7-9ft window, it has 0.5 - 0.09 = 0.41 s or less to reverse its acceleration and go back to the original spot to take care of the next drop.
So at 9ft, the drop and camera velocity would be:
So if the camera reverses its direction to go back to original spot at the rate of a (ft/s2) and initial speed of 24.1 ft/s. Within the time span of 0.41s to catch the next drop at 7ft
So the camera would flow the same velocity and acceleration of the droplet until 9ft. After that it would switch gear and accelerate back to its original spot at the rate of 140.54 m/s2 in order to catch the next droplet.