In snakes, being rude ( R ) is dominant to being respectful (r), and being sneaky (S) is dominant to being sincere (s). A female
snake that is homozygous recessive for both the r and s trait is mated with a male snake that is homozygous dominant for both traits (R and S). Both the R and S traits assort independently from one another. What is the probability that they will have an offspring that is respectful and sincere?
1 answer:
Answer:
Zero (0).
Explanation:
As per the question, the male snake will have genotype RRSS while the female snake will have genotype rrss. The male snake will produce 4 identical gametes which will have "RS" genetic combination while female snake will produce 4 identical gametes with "rs" genetic combination.
The cross depicting the genotypes of their off-springs is attached.
It is clear from the "Punnett square diagram" that all their progeny will have "RrSs genotype" which simply means that all the progeny will be heterozygous dominant and therefore phenotypically they all will be rude and sneaky. It also implies that no progeny will have rrss genotype which could make it respectful and sincere so the probability is zero.
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<h2>Maternal effect</h2>
Explanation:
In maternal effect the phenotype of the progeny is decided by the genotype of the mother
- The female partner is one step ahead to her male partner
- The ovum transcribes some of its nuclear genes prior to fertilization and these genes are responsible for the development of embryo that is why these genes are called maternal effect genes
- This effect is observed in Drosophila
In the given question both male and female have brown eyes with Nn genotype,phenotype of the offspring will be decided by the genotype of mother(Nn) hence despite of having recessive genotype(nn) all the offsprings will show brown eyes