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gtnhenbr [62]
2 years ago
6

A large open meadow near your city is shrinking in size because developers have started building new homes there.

Mathematics
1 answer:
valentinak56 [21]2 years ago
8 0

Answer:

    t=-10\log 0.32

Explanation:

<u>Equation:</u>

         A=1,562.5\times 10^{(-0.1t)}

This is a decaying exponential function, because the exponent is negative.

Then, the larger the value of t (number of months), the smaller A (the number of hectares).

The factor 1,562.5 is the initial number of hecares, when t = 0.

You must find the value of t when A equals 500, thus solve the equation:

     500=1,562.5\times 10^{(-0.1t)

Divide both sides by 1,562.5

     \dfrac{500}{1,562.5}=10^{(-0.1t)}

    0.32=10^{(-0.1t)}

Take base-10 logarithms on both sides:

    \log 0.32=-0.1t

    t=-\dfrac{\log 0.32}{0.1}\\\\\\t=-10\log 0.32

Note that the logarithm of a number decimal number is negative number, thus t will be positive. When you compute that, it is about 4.9 months.

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A feather blew out of a bird nest 10 feet in the air. It drifted to the ground at a constant rate of 2 feet per second. Write an
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The answer would be 10/2=5
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1 year ago
Suppose that the IQs of university​ A's students can be described by a normal model with mean 140 and standard deviation 8 poi
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Answer:

0.0266, 0.9997,0.7856

Step-by-step explanation:

Given that the IQs of university​ A's students can be described by a normal model with mean 140 and standard deviation 8 points. Also suppose that IQs of students from university B can be described by a normal model with mean 120 and standard deviation 11. Let x be the score by A students and Y the score of B.

A)P(X>135) = \\P(Z>0.625)\\=0.0266

B) Since X and Y are independent we have

X-Y is Normal with mean = 140-120 =20 and Var (x-y)=Var(x)+Var(y) = 19

P(X-Y)>5\\\\=1-0.00029\\=0.9997

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P(\bar y >115)\\= P(z>\frac{-5}{6.351} \\=0.7856

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Pecans that cost $28.50 per kilogram were mixed with almonds that cost $22.25 per kilogram. How many kilograms of each were used
atroni [7]

Answer:

The pecans used in the mixture =  8 kg

The almonds used in the mixture  =  17 kg

Step-by-step explanation:

The cost of per kg of pecans  = $28.50

The cost of per kg of almonds = $22.25

Now, total weight of mixture  = 25 kg

Let us assume the weight of pecans in the mixture   =   m kg

So, the amount of almonds in the mixture  = Total weight - Weight of Pecans

= (25 - m) kg

Now, cost of m kg pecans  = m x ( cost of 1 kg pecans) = m x ( $ 28.50)

                                              =  28.50 m

cost of (25- m) kg almonds  = (25 -m)  x ( cost of 1 kg almonds)

                                                = (25 - m) x ( $ 22.25)

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Total cost  of 25 kg of mixture  = 25 x ( $24.25) =  $606.25

Now, Total Cost of (almonds  + Pecans)  = Total cost of mixture

⇒28.50 m + 556.25  - 22.25 m  = $606.25

or,6.25 m =  50

or, m = 50/6.25 =  8

Hence, the pecans used in the mixture = m = 8 kg

And the  almonds used in the mixture  = (25 - m) = 25 - 8 = 17 kg

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