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wel
2 years ago
4

A certain quantity has a century decay factor of 0.5. What is its yearly decay factor? (Round your answer to two decimal places.

)
Mathematics
1 answer:
larisa86 [58]2 years ago
7 0

Answer:

0.01.

Step-by-step explanation:

We have been given that a certain certain quantity has a century decay factor of 0.5. We are asked to find yearly decay factor of the given quantity.

We know that decay factor is in form (1-r)^x, where r represents decay rate in decimal form and x is time.

We can represent our given information in an equation as:  

(1-r)^{100}=0.5

Upon taking hundredth root on both sides, we will get:

\sqrt[100]{(1-r)^{100}}=\sqrt[100]{0.5}

1-r=0.9930924954370359

1-1-r=0.9930924954370359-1

-r=-0.0069075045629641

Multiplying both sides by -1, we will get:

r=0.0069075045629641

Upon rounding to two decimal places, we will get:

r\approx 0.01

Therefore, the yearly decay rate is approximately 0.01.

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2 years ago
A car tire with a radius of 16inches is turning at a rate of 120 revolutions per minute. Find the exact linear speed of the tire
anygoal [31]

Answer:

The speed of the tyre of the car is 1002.24 feet per minute .

Step-by-step explanation:

Given as :

The radius of the car wheel = r = 16 inches

Since 12 inches = 1 feet

So,  16 inches = \frac{1}{12}×16 = 1.33 feet

The number of revolution of the wheel = 120 revolution per minute

Let The speed of the wheel = s feet per minute

The circumference of wheel = 2 × \pi × radius

where  \pi  = 3.14

or, circumference =  2 × 3.14 × 1.33

Or, Circumference = 8.352 feet

Now , Speed =  circumference of wheel × number of revolution

or, Speed = 8.352 feet × 120 revolution per minute

∴ Speed = 1002.24 feet per minute

Hence The speed of the tyre of the car is 1002.24 feet per minute . Answer

4 0
3 years ago
Ramon has 6.75 kg coffee. he wants 0.25 kg bags. how many bags does he need?
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Answer:

Ramon would need 27 bags

Step-by-step explanation:

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5 0
2 years ago
A marketing representative wants to estimate the proportion of people in a state who like the new design on the packaging of a c
Effectus [21]

Answer:

The correct option is;

(B) Yes, because sampling distributions of population proportions are modeled with a normal model.

Step-by-step explanation:

Here we have the condition for normality being that where we have a population with a given mean and standard deviation, while a sufficiently large sample is drawn from the population while being replaced, the distribution of the sample mean p will be distributed normally according to central limit theorem.

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2 years ago
A company manufacturing oil seals wants to establish X and R control charts on the process. There are 25 preliminary samples of
alisha [4.7K]

Answer:

A ) i) X control chart : upper limit = 50.475, lower limit = 49.825

    ii) R control chart : upper limit =  1.191, lower limit = 0

Step-by-step explanation:

A) Finding the control limits

grand sample mean = 1253.75 / 25 = 50.15

mean range = 14.08 / 25 = 0.5632

Based on  X control CHART

The upper control limit ( UCL ) =

grand sample mean + A2* mean range ) = 50.15 + 0.577(0.5632) = 50.475

The lower control limit (LCL)=

grand sample mean - A2 *  mean range = 50.15 - 0.577(0.5632) = 49.825

Based on  R control charts

The upper limit = D4 * mean range = 2.114 * 0.5632 = 1.191

The lower control limit = D3 * mean range = 0 * 0.5632 = 0  

B) estimate the process mean and standard deviation

estimated process mean = 50.15 = grand sample mean

standard deviation = mean range / d2  = 0.5632 / 2.326 = 0.2421

note d2 is obtained from control table

6 0
2 years ago
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