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2 years ago

The binomial (y − 2) is a factor of y2 − 10y + 16. What is the other factor?

Mathematics

2 answers:

PtichkaEL [24]2 years ago

5 0

Answer:

$\left(y-8\right)$

Step-by-step explanation:

$y^2-10y+16$

$=\left(y^2-2y\right)+\left(-8y+16\right)$

$y^2-2y$

$=yy-2y$

$=y\left(y-2\right)$

$-8y+16$

$=-8y+8\cdot \:2$

$=-8\left(y-2\right)$

$=y\left(y-2\right)-8\left(y-2\right)$

$=\left(y-2\right)\left(y-8\right)$

The other factor is:

$\left(y-8\right)$

lorasvet [3.4K]2 years ago

3 0

Incase it helps to have a slightly different approach, the way we learnt it is:

y2 - 10y + 16 = 0

When these are factorised, the brackets you have will need to expand to equal the above.

You need to find 2 numbers that multiply together to make the end number, c, and those 2 numbers must also add together to made the middle number, b.

So for this case, those two numbers would be -2 and -8.

Then these go into the brackets,
(y - 2) (y - 8) = 0

This can then be proven to be correct via expansion,

y x y = y2
y x -8 = -8y
-2 x y = -2y
-2 x -8 = 16

(y2) + (-8y) + (-2y) + (16) = 0

y2 - 8y - 2y + 16 = 0

y2 - 10y + 16 = 0

Hope this helps a little?

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Let X represent the amount of gasoline (gallons) purchased by a randomly selected customer at a gas station. Suppose that the me

Alexus [3.1K]

Answer:

a) 18.94% probability that the sample mean amount purchased is at least 12 gallons

b) 81.06% probability that the total amount of gasoline purchased is at most 600 gallons.

c) The approximate value of the 95th percentile for the total amount purchased by 50 randomly selected customers is 621.5 gallons.

Step-by-step explanation:

To solve this question, we use the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums, we can apply the theorem, with mean $\mu$ and standard deviation $s = \sqrt{n}*\sigma$

In this problem, we have that:

$\mu = 11.5, \sigma = 4$

a. In a sample of 50 randomly selected customers, what is the approximate probability that the sample mean amount purchased is at least 12 gallons?

Here we have $n = 50, s = \frac{4}{\sqrt{50}} = 0.5657$

This probability is 1 subtracted by the pvalue of Z when X = 12.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{12 - 11.5}{0.5657}$

$Z = 0.88$

$Z = 0.88$ has a pvalue of 0.8106.

1 - 0.8106 = 0.1894

18.94% probability that the sample mean amount purchased is at least 12 gallons

b. In a sample of 50 randomly selected customers, what is the approximate probability that the total amount of gasoline purchased is at most 600 gallons.

For sums, so $mu = 50*11.5 = 575, s = \sqrt{50}*4 = 28.28$

This probability is the pvalue of Z when X = 600. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{600 - 575}{28.28}$

$Z = 0.88$

$Z = 0.88$ has a pvalue of 0.8106.

81.06% probability that the total amount of gasoline purchased is at most 600 gallons.

c. What is the approximate value of the 95th percentile for the total amount purchased by 50 randomly selected customers.

This is X when Z has a pvalue of 0.95. So it is X when Z = 1.645.

$Z = \frac{X - \mu}{s}$

$1.645 = \frac{X- 575}{28.28}$

$X - 575 = 28.28*1.645$

$X = 621.5$

The approximate value of the 95th percentile for the total amount purchased by 50 randomly selected customers is 621.5 gallons.

5 0

2 years ago

The length of the bar for a high jump competition must always be 4.75 m. Express this measurement in millimeters. Explain your t

Elena-2011 [213]

4,750 mm

Equation with an exponent 4.75 x $10^{3}$ = 4,750

First, it's important to know that there are 1,000 millimeters in 1 meter. Second, it's important to know that $10^{3}$ is the same as 1,000. In order to find out how many millimeters are in 4.75 meters, one must multiply 4.75 by 1,000.

<h3>Further Explanation</h3>

Meters

A meter is a unit of metric measurement. Track and Field events use the metric system because it is a universal unit of measurement. Inches and feet are not units used all over the world. The Olympic Games use the metric system so this is the system that is universally adopted throughout the world for many sporting events, including track and field. Sports that are more commonly attributed to the USA and not an Olympic event often uses the US system. An example is football. The field is measured in yards instead of meters.

Millimeters

The prefix milli- means 1,000. Often it is used to denote a thousandth unit of measurement in the metric system. This is a useful item to know because it can be applied to many different math terms such as millimeters or milliliters.

Exponents

An exponent is the amount of times a number is multiplied to itself. For example $4^{2}$ is the same as 4 x 4 = 16. This is a faster way to write repeated multiplication.