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Vinil7 [7]
1 year ago
11

What is 974.362 rounded to the nearest ten

Mathematics
1 answer:
Murrr4er [49]1 year ago
7 0
<span>The tens place of the given number 974.362 is 7. To round it to the nearest ten then is should remain the same because the ones digit is equal to 4, the tens digit so be retained because it is less than 5.</span> <span>So the answer is 970</span>
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An investor has $ 500000 to spend. There investments are being considered, each having an expected annual interest rate. The int
enyata [817]
That's a lot of money and words. I don't appreciate this. I would probably just break down and cry tbh
8 0
2 years ago
the weight of a bag of golf balls varies directly as the number of golf balls in the bag.If a bag of 69 gold balls weighs 2,553
seropon [69]

Answer: 30

Step-by-step explanation:

Given :The weight of a bag of golf balls varies directly as the number of golf balls in the bag.

Let x be the number of golf balls in a bag that weighs 1,110 grams.

Then we have the following direct variation equation,

\dfrac{x}{1110}=\dfrac{69}{2553}

Multiply 1110 both sides , we get

x=\dfrac{69}{2553}\times1110=30

Hence, there are 30 balls in the bag.

4 0
1 year ago
A rice merchant purchased 50 bags of rice at rupees 300 per back he spent 500 rupees towards transportation due to lack of deman
Alex777 [14]

Answer:

10500 rupees

Step-by-step explanation:

So 50 bags 300 per pack so

300*50= 15000

15000 is what he spent on the 50 bags of rice

So he spent 500 rupees on transportation

15000 + 500 = 15500 total spent which is not needed but extra information

30% loss is 30% of 15000 so

30% of 15000 = 4500

15000 - 4500 = 10500 rupees

8 0
1 year ago
PLEASE HELP ME!
algol13

Step-by-step explanation:

1.\sum_{i=1}^{5}3i

The simplest method is "brute force".  Calculate each term and add them up.

∑ = 3(1) + 3(2) + 3(3) + 3(4) + 3(5)

∑ = 3 + 6 + 9 + 12 + 15

∑ = 45

2.\sum_{k=1}^{4}(2k)^{2}

∑ = (2×1)² + (2×2)² + (2×3)² + (2×4)²

∑ = 4 + 16 + 36 + 64

∑ = 120

3.\sum_{k=3}^{6}(2k-10)

∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)

∑ = -4 + -2 + 0 + 2

∑ = -4

4. 1 + 1/4 + 1/16 + 1/64 + 1/256

This is a geometric sequence where the first term is 1 and the common ratio is 1/4.  The nth term is:

a = 1 (1/4)ⁿ⁻¹

So the series is:

\sum_{j=1}^{7}(\frac{1}{4})^{j-1}

5. -5 + -1 + 3 + 7 + 11

This is an arithmetic sequence where the first term is -5 and the common difference is 4.  The nth term is:

a = -5 + 4(n−1)

a = -5 + 4n − 4

a = 4n − 9

So the series is:

\sum_{j=1}^{5}(4j-9)

5 0
2 years ago
The rule for the dilation of quadrilateral QRST to the image Q'R'S'T' is DO,0.5(x, y) → (0.5x, 0.5y).
Harlamova29_29 [7]
Applying the rule for dilation, we will multiply the scale factor to its coordinates. 
Having Q (0,2) and DO 0.5(x.y), the coordinates of Q' will be:

x = (.5)(0) = 0
y = (.5)(2) = 1

Therefore coordinates of Q' is (0,1) 

*Having a scale factor of >1, the figure is said to be reduced. 
8 0
1 year ago
Read 2 more answers
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