Answer:
Given: A triangle ABC and a line DE parallel to BC.
To prove: A line parallel to one side of a triangle divides the other two sides proportionally.
Proof: Consider ΔABC and DE be the line parallel to Bc, then from ΔABC and ΔADE, we have
∠A=∠A (Common)
∠ADE=∠ABC (Corresponding angles)
Thus, by AA similarity, ΔABC is similar to ΔADE, therefore
AB/AD= AC/AE
⇒AD+DB/AD = AE+EC/AE
⇒1+DB/AD = 1+ EC/AE
⇒DB/AD = EC/AE
Therefore, a line parallel to one side of a triangle divides the other two sides proportionally.
⇒Therefore Proved
Hope this helps!!!
Answer:
17/4 kg
Step-by-step explanation:
Sunita has = 10kg of grapes
Quantity given out :
To Reena =3 1/2
7/2 kg
To Anita =2 1/4
9/4 kg
Total quantity of grape given out
7/2+9/4
(14+9)/4
23/4
Quantity left after giving out = Total quantity of grape before giving out minus quantity of grape given out
10/1 - 23/4
40-23)/4
= 17/4 or 4 1/4
Hence, she has 17/4 kg of grape left with her
Let us say weight of Javier is x pounds.
Weight of his bother = 80 pounds
Javier is 175 % or 1.75 times heavier than his brother.
So Javier's weight = x pounds= 1.75 *80 = 140 pounds.
Answer: Javier's weight is 140 pounds.
