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Flura [38]
2 years ago
12

If the relationship between y and x is given by the equation y = 1.57 − 0.0407 x, the slope coefficient 0.0407 means this: _____

_____. for every unit increase in x, y decreases by 1.5293 for every unit increase in x, y increases by 1.5293 for every unit increase in x, y increases by 0.0407 for every unit increase in x, y decreases by 0.0407
Mathematics
1 answer:
telo118 [61]2 years ago
8 0

Answer:

The correct answer is for every unit increase in x, y decreases by 0.0407.

Step-by-step explanation:

The equation of the line between x and y is given by y = 1.57 - 0.0407x.

The slope coefficient of this line is -0.0407.

The slope (\frac{y - y1}{x - x1}) is negative and thus there is a negative relation between the two variable, i.e. the numerator (y - y1) should decrease as (x - x1) is increasing.

For x = -2 , the value of y is 1.6514.

For x = -1 , the value of y is 1.6107.

For x = 0 , the value of y is 1.57.

For x = 1 , the value of y is 1.5293.

For x = 2 , the value of y is 1.4886.

Thus for every unit increase in x we can see a decrease by 0.0407 in the variable y.

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Which point on the y-axis lies on the line that passes through point C and is perpendicular to line AB?
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The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Which point on the y-axis lies on the line that passes through point C and is perpendicular to line AB?

A. (-6, 0)

B. (0, -6)

C. (0, 2)

D. (2, 0)

The graph of the question is attached.

Answer:

The point is (x, y) = (0, 2)

The correct option is C.

Therefore, the point (0, 2) on the y-axis lies on the line that passes through point C and is perpendicular to line AB.

Step-by-step explanation:

From the given graph, the points A and B are

(x_1, y_1) = (-2, 4) \\\\(x_2, y_2) = (2,-8) \\\\

The slope of the equation is given by

m_1 = \frac{-8 - 4 }{2 -(-2)} \\\\ m_1 = \frac{-12 }{2+2} \\\\m_1 = \frac{-12 }{4} \\\\m_1 = -3 \\\\

We know that the slopes of two perpendicular lines are negative reciprocals of each other.

m_2 = - \frac{1}{m_1}

So the slope of the other line is

m_2 = \frac{1 }{3} \\\\

Now we can find the equation of the line that is perpendicular to the line AB and passes through the point C.

From the graph, the coordinates of point C are

(x_1, y_1) = (6, 4)

The point-slope form is given by,

y - y_1 = m(x -x_1)

Substitute the value of slope and the coordinates of point C

y - 4 = \frac{1 }{3} (x - 6)\\\\

To get the y-intercept, substitute x = 0  

y - 4 = \frac{1 }{3} (0 - 6) \\\\y - 4 = \frac{-6 }{3}\\\\y - 4 = -2\\\\y = 4 -2 \\\\y = 2 \\\\

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(x, y) = (0, 2)

The correct option is C.

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