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AnnyKZ [126]
2 years ago
15

1. What might you say to someone whose reason for investing in 90% bonds and 10% stocks is that they want a 6% return on investm

ent?
2. Use evidence from this graph to explain the value of investing in both stocks and bonds - not just one or the other.

Computers and Technology
1 answer:
Gemiola [76]2 years ago
5 0

Investing in 90% bonds and 10% stocks will provide an average return of 6% on investment.It is advisable to invest more portion in bonds  is safe and will give higher return for investment than stocks

Explanation:

1. According to the graph investing in 90% bonds and 10% stocks will provide an average return of 6% on investment.

2.Investing in bonds is safe than stocks ., because bonds bear fixed rate of interest ., and investing in the bonds having very less risk than the stocks. By comparing stocks and bonds with the help of graph ., it's very clear bonds has a positive growth starting minimum at 32.6% to maximum at 64.2% as returns .But stocks has a negative growth (value) from -8.2% to maximum -43.1% .,It is advisable to invest more portions in bonds is safe and better than invest in stocks.

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Our company is only interested in purchasing a software upgrade if it leads to faster connectivity and data sharing. The old sof
Igoryamba

Answer:

Calculate the average processing time of the new software

Explanation:

Since the average processing time of the old software is already known, the simplest test to see if the new software is faster than the old software will be to calculate the average processing time for the new software and compare it with the average processing time of the old software.

If the new software have an average processing time lower/smaller than that of the old software; we conclude that the new software is faster.

If the new software have an average processing time higher/larger than that of the old software; we conclude that the old software is faster.

6 0
2 years ago
The hostel in which you plan to spend the night tonight offers very interesting rates, as long as you do not arrive too late. Ho
faust18 [17]

Answer:

Answered below

Explanation:

// Python implementation

incrementAmount = 5

basePrice = 10

price = 0

arrivalHour = int(input("Enter arrival hour 0-12: ")

if arrivalHour < 0 or arrivalHour > 12:

print ("Invalid hour")

if arrivalHour == 0:

price = basePrice

else:

price = arrivalHour * incrementAmount

totalPrice = price + basePrice

if totalPrice > 53:

totalPrice = 53

print ("Your bill is $totalPrice")

4 0
2 years ago
This question involves the creation of user names for an online system. A user name is created based on a user’s first and last
Evgen [1.6K]

Answer:

See explaination

Explanation:

import java.util.*;

class UserName{

ArrayList<String> possibleNames;

UserName(String firstName, String lastName){

if(this.isValidName(firstName) && this.isValidName(lastName)){

possibleNames = new ArrayList<String>();

for(int i=1;i<firstName.length()+1;i++){

possibleNames.add(lastName+firstName.substring(0,i));

}

}else{

System.out.println("firstName and lastName must contain letters only.");

}

}

public boolean isUsed(String name, String[] arr){

for(int i=0;i<arr.length;i++){

if(name.equals(arr[i]))

return true;

}

return false;

}

public void setAvailableUserNames(String[] usedNames){

String[] names = new String[this.possibleNames.size()];

names = this.possibleNames.toArray(names);

for(int i=0;i<usedNames.length;i++){

if(isUsed(usedNames[i],names)){

int index = this.possibleNames.indexOf(usedNames[i]);

this.possibleNames.remove(index);

names = new String[this.possibleNames.size()];

names = this.possibleNames.toArray(names);

}

}

}

public boolean isValidName(String str){

if(str.length()==0) return false;

for(int i=0;i<str.length();i++){

if(str.charAt(i)<'a'||str.charAt(i)>'z' && (str.charAt(i)<'A' || str.charAt(i)>'Z'))

return false;

}

return true;

}

public static void main(String[] args) {

UserName person1 = new UserName("john","smith");

System.out.println(person1.possibleNames);

String[] used = {"harta","hartm","harty"};

UserName person2 = new UserName("mary","hart");

System.out.println("possibleNames before removing: "+person2.possibleNames);

person2.setAvailableUserNames(used);

System.out.println("possibleNames after removing: "+person2.possibleNames);

}

}

8 0
2 years ago
Match the careers with the career clusters.
creativ13 [48]
<h2>Answer and Explanation:</h2>

The picture shows the right careers with their respective career clusters.

4 0
2 years ago
Read 2 more answers
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IceJOKER [234]

Answer:

Below is the required code:

Explanation:

SELECT Product_Finish AS "Desk Finish",

avg(Standard_Price) AS "Average Price"

FROM Product_T

WHERE "Average Price">200

ORDER BY "Average Price" DESC;

8 0
2 years ago
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