A) 15/4 = 4/4+4/4+4/4+3/4= 3 3/4
B)9/2= 2/2+2/2+2/2+2/2+1/2= 4 1/2
c = 26/12 = 12/12 + 12/12 + 2/12 = 2 2/12
d) 20/6 = 6/6 + 6/6 + 6/6 + 2/6 = 3 2/6
Answer:
The center/ mean will almost be equal, and the variability of simulation B will be higher than the variability of simulation A.
Step-by-step explanation:
Solution
Normally, a distribution sample is mostly affected by sample size.
As a rule, sampling error decreases by half by increasing the sample size four times.
In this case, B sample is 2 times higher the A sample size.
Now, the Mean sampling error is affected and is not higher for A.
But it's sample is huge for this, Thus, they are almost equal
Variability of simulation decreases with increase in number of trials. A has less variability.
With increase number of trials, variability of simulation decreases, so A has less variability.
Given maria has 
in the pennies & quarters.
she has twice as many pennies as quarters.
find out the coins
let us assume the quarters are x
than the pennies are 2x.
Formula
value of the pennies + value of the quarters = total value of coins
1 quarters =$ 0.25
1 pennies = $0.01
Thus
0.25x + 0.01 (2x) = 2.43
0.27 x = 2.43
x = 9
2x = 18
i.e the number of quarters are 9 and the number of pennies are 18.
Hence proved
Answer:
1/48
Step-by-step explanation:
The probability of both happening is equal to the product of each probability.
P(A and B) = P(A) × P(B)
P = 1/12 × 1/4
P = 1/48
From the given figure, it can be seen that 13x = 15x - 8 because they are vertical angles and thus are equal.
13x = 15x - 8
15x - 13x = 8
2x = 8
x = 8/2 = 4
Thus, 15x - 8 = 15(4) - 8 = 60 - 8 = 52.
RT is a diameter, which means that mRT = 180
mRV + mVU + 52 = 180
mRV + mVU = 180 - 52 = 128
Now, given that mRV = mVU,
Thus, 2mVU = 128
Therefore, mVU = 128 / 2 = 64°
