Maria has $2.43 in quarters and pennies in her wallet. She has twice as many pennies as quarters. How many coins of each type do
2 answers:
Given maria has in the pennies & quarters.
she has twice as many pennies as quarters.
find out the coins
let us assume the quarters are x
than the pennies are 2x.
Formula
value of the pennies + value of the quarters = total value of coins
1 quarters =$ 0.25
1 pennies = $0.01
Thus
0.25x + 0.01 (2x) = 2.43
0.27 x = 2.43
x = 9
2x = 18
i.e the number of quarters are 9 and the number of pennies are 18.
Hence proved
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Answer:
Porter is inches taller than Henry.
Porter is times taller than henry.
Step-by-step explanation:
The difference in height can be found using subtraction.
Since Porter is taller than Henry, we'll subtract away Henry's height from Porter's height. This will leave us with only the difference between the heights.
n = Porter's height
m = Henry's height
Difference in height is thus:
Answer: Porter is inches taller than Henry.
To find out how many times taller Porter is than Henry, we can use division.
An example: if Porter was 200cm, and Henry was 100cm, Porter is obviously 2 times as tall.
If we divide Porter's height by Henry's height...
..we'll get 2. This is because Henry's height "fits in twice" in Porter's height. 100 fits twice in 200.
Using our values, n and m, we'll divide n by m.
Answer: Porter is times taller than henry.
Jalen has total 63 comic books.
Step-by-step explanation:
Given,
Total value of comic books = $3135
Let,
Number of $45 comic books = x
Number of $65 comic books = y
According to given statement;
45x+65y=3135 Eqn 1
x=y+33 Eqn 2
Putting value of x from Eqn 2 in Eqn 1
Dividing both sides by 110
Putting y=15 in Eqn 2
Total comic books = x+y
Total comic books = 48+15 = 63
Jalen has total 63 comic books.
Keywords: addition, elimination method
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Answer:
The 88% confidence interval for the proportion of defectives today is (0.053, 0.123)
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
For this problem, we have that:
88% confidence level
So , z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 88% confidence interval for the proportion of defectives today is (0.053, 0.123)