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klio [65]
2 years ago
3

According to the American Red Cross, 9.2% of all Connecticut residents have Type B blood. A random sample of 18 Connecticut resi

dents is taken. What is the standard deviation of the random variable X?
Mathematics
1 answer:
Bess [88]2 years ago
4 0

Answer:

The standard deviation of the random variable X is 1.23.

Step-by-step explanation:

For each Connecticut resident, there are only two possible outcomes. Either they have Type B blood, or they do not. The probability of a resident having type B blood is independent of other residents. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

9.2% of all Connecticut residents have Type B blood.

This means that p = 0.092

A random sample of 18 Connecticut residents is taken.

This means that n = 18

What is the standard deviation of the random variable X?

\sqrt{V(X)} = \sqrt{18*0.092*0.908} = 1.23

The standard deviation of the random variable X is 1.23.

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Compare this with x^2+kx+30 and we see that k = 13

Factor and solve the equation below

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2 years ago
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In a certain community, eight percent of all adults over age 50 have diabetes. If a health service in this community correctly d
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Complete question is;

In a certain community, 8% of all people above 50 years of age have diabetes. A health service in this community correctly diagnoses 95% of all person with diabetes as having the disease, and incorrectly diagnoses 10% of all person without diabetes as having the disease. Find the probability that a person randomly selected from among all people of age above 50 and diagnosed by the health service as having diabetes actually has the disease.

Answer:

P(has diabetes | positive) = 0.442

Step-by-step explanation:

Probability of having diabetes and being positive is;

P(positive & has diabetes) = P(has diabetes) × P(positive | has diabetes)

We are told 8% or 0.08 have diabetes and there's a correct diagnosis of 95% of all the persons with diabetes having the disease.

Thus;

P(positive & has diabetes) = 0.08 × 0.95 = 0.076

P(negative & has diabetes) = P(has diabetes) × (1 –P(positive | has diabetes)) = 0.08 × (1 - 0.95)

P(negative & has diabetes) = 0.004

P(positive & no diabetes) = P(no diabetes) × P(positive | no diabetes)

We are told that there is an incorrect diagnoses of 10% of all persons without diabetes as having the disease

Thus;

P(positive & no diabetes) = 0.92 × 0.1 = 0.092

P(negative &no diabetes) =P(no diabetes) × (1 –P(positive | no diabetes)) = 0.92 × (1 - 0.1)

P(negative &no diabetes) = 0.828

Probability that a person selected having diabetes actually has the disease is;

P(has diabetes | positive) =P(positive & has diabetes) / P(positive)

P(positive) = 0.08 + P(positive & no diabetes)

P(positive) = 0.08 + 0.092 = 0.172

P(has diabetes | positive) = 0.076/0.172 = 0.442

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The cost of producing x bags of dog food is given by C(x) = 800 + 400 + 10x - x where 0 SX 55000. Find the marginal-cost functio
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Answer:

The marginal-cost function is;

c'(x)= (20x-1)/(2√(400 + 10x² - x))

Completed question;

The cost of producing x bags of dog food is given by C(x) = 800 + √(400 + 10x² - x) where 0≤x≤55000. Find the marginal-cost function.

The marginal-cost function is c'(x)=

(Use integers or fractions for any numbers in the expression.)

Step-by-step explanation:

The marginal-cost function is c'(x)= = dC(x)/dx

Where;

C(x) = 800 + √(400 + 10x² - x)

c'(x) = d(800 + √(400 + 10x² - x) )/dx

Using function of function rule of differentiation or chain rule;

c'(x) = (20x-1)×(1/2√(400 + 10x² - x))

c'(x) = (20x-1)/(2√(400 + 10x² - x))

The marginal-cost function is;

c'(x)= (20x-1)/(2√(400 + 10x² - x))

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