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marshall27 [118]
1 year ago
14

if you apply 20 newtons of force to do 60 joules of work on an object moves a distance of ---------- meters

Mathematics
1 answer:
IgorLugansk [536]1 year ago
3 0

Answer:

3 metres

Step-by-step explanation:

Work done = Force × displacement

60= 20×d

d= 60/20

d= 3 metres

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Sin(19)

Use your calculator.

sin(19) = 0.3255681545
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1 year ago
Bob spent $64 for two shirts, including tax. The difference between the costs of the shirts was $16. Write two equations that yo
djyliett [7]

x+y=64 and x-y=16 can be used to solve the system.

Step-by-step explanation:

Let,

x,y be the two shirts.

According to given statement;

Bob spent $64 on both shirts;

x+y=64    Eqn 1

The difference between the costs of the shirts was $16 means subtraction;

x-y=16      Eqn 2

x+y=64 and x-y=16 can be used to solve the system.

Keywords: linear equation, addition

Learn more about linear equations at:

  • brainly.com/question/902892
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#LearnwithBrainly

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1 year ago
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Kelly asked some of her classmates how many hours of sleep they get on school nights. Here are the results:
Hitman42 [59]

All three are equal to 8

5 0
1 year ago
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A baseball player has 39 hits in 134 times at bat. how many hits must he get in the next 46 times at bat to finish the year with
faust18 [17]

Answer:

He must get 33 hits in his next 46 times at bat to finish the year with a .400 batting average

Step-by-step explanation:

The player has already batted 134 times and will still bat 46 times. So in the end of the year, he is going to have 134 + 46 = 180 at bats.

How many hits does he need to have to hit .400?

This is 40% of 180, which is 0.4*180 = 72.

He has already 39 hits, so in his next 46 at bats, he will need 72 - 39 = 33 hits.

4 0
2 years ago
Find the dimensions of the box with volume 1728 cm3 that has minimal surface area. (Let x, y, and z be the dimensions of the box
Gala2k [10]

Answer:

The dimensions of the box are 12 cm , 12 cm , 12 cm

Step-by-step explanation:

Let x , y and z be the dimensions of box

Volume of box =xyz=1728

z=\frac{1728}{xy}

Surface area of box = 2xy+2yz+2xz=2xy+2y(\frac{1728}{xy})+2x(\frac{1728}{xy})

Let f(x,y)=2xy+2(\frac{1728}{x})+2(\frac{1728}{y})

To get minimal surface area

\frac{\partial f}{\partial x}=0 and \frac{\partial f}{\partial y}=0

\frac{\partial(2xy+2(\frac{1728}{x})+2(\frac{1728}{y}))}{\partial x}=0

2y-2(\frac{1728}{x^2})=0

y=\frac{1728}{x^2} ----1

\frac{\partial(2xy+2(\frac{1728}{x})+2(\frac{1728}{y}))}{\partial y}=0

2x-2(\frac{1728}{y^2})=0\\x=\frac{1728}{y^2}  \\y^2=\frac{1728}{x}

Using 1

(\frac{1728}{x^2} )^2=\frac{1728}{x}

x=0 and x^3=1728

Side can never be 0

So,x^3=1728

x=12

y=\frac{1728}{x^2} \\y=\frac{1728}{12^2}

y=12

z=\frac{1728}{xy}\\z=\frac{1728}{(12)(12)}

z=12

The dimensions of the box are 12 cm , 12 cm , 12 cm

5 0
1 year ago
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