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2 years ago

Suppose chocolate costs $17.60 per kilogram. Karega buys 25 grams of chocolate and Samadhi buys 100 grams of chocolate.

1 answer:

5 0

Answer:
$1.32

Explanation:
For 25 grams it costs $0.44 and for 100 grams it costs $1.76 so Samadhi payed $1.32 more than Karega.

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Help quick The engineers designing the All Aboard Railroad between Boca Raton and Jupiter decide to create parallel tracks throu

QveST [7]

Answer:

Do you have answer choices

Step-by-step explanation:

8 0

2 years ago

Printed circuit cards are placed in a functional test after being populated with semiconductor chips. A lot contains 140 cards,

hjlf

Answer:

a) 0.9644 or 96.44%

b) 0.5429 or 54.29%

Step-by-step explanation:

a) The probability that at least 1 defective card is in the sample P(A) = 1 - probability that no defective card is in the sample P(N)

P(A) = 1 - P(N) .....1

Given;

Total number of cards = 140

Number selected = 20

Total number of defective cards = 20

Total number of non defective cards = 140-20 = 120

P(N) = Number of possible selections of 20 non defective cards ÷ Number of possible selections of 20 cards from all the cards.

P(N) = 120C20/140C20 = 0.0356

From equation 1

P(A) = 1 - 0.0356

P(A) = 0.9644 or 96.44%

b) Using the same method as a) above

P(A) = 1 - P(N) .....1

Given;

Total number of cards = 140

Number selected = 20

Total number of defective cards = 5

Total number of non defective cards = 140-5 = 135

P(N) = 135C20/140C20 = 0.457

From equation 1

P(A) = 1 - 0.4571

P(A) = 0.5429 or 54.29%

8 0

2 years ago

A contractor has submitted bids on three state jobs: an office building, a theater, and a parking garage. State rules do not all

german

Answer:

The following are the answer to this question:

Step-by-step explanation:

In the given question the numeric value is missing which is defined in the attached file please fine it.

Calculating the probability of the distribution for x:

$\to f(x) = 0.19\ for \ x=14\\\\\to f(x) = 0.29 \ for\ x=7\\\\\to f(x) = 0.38\ for \ x=1\\\\\to f(x)=0.14 \ for \ x=0\\$

The formula for calculating the mean value:

$\bold{ E(X)= x \times f(x)}$

$=14 \times 0.19+7 \times 0.29+1 \times 0.38+0\times 0.14\\\\=2.66 + 2.03+0.38+ 0\\\\=5.07$

$\bold{E(X^2) = x^2 \times f(x)}$

$=14^2 \times 0.19+7^2 \times 0.29+1^2 \times 0.38+0^2 \times 0.14 \\\\=196 \times 0.19+ 49 \times 0.29+1 \times 0.38+0 \times 0.14\\\\= 37.24+ 14.21+ 0.38+0 \\\\=51.83$

use formula for calculating the Variance:

$\to \bold{\text{Variance}= E(X^2) -[E(X)]^2}$

$= 51.83 - (5.07)^2\\\\= 51.83 - 25.70\\\\=26.13$

calculating the value of standard deivation:

Standard Deivation (SD) = $\sqrt{Variance}$

$= \sqrt{26.13} \\\\=5.111$

6 0

2 years ago

The school cafeteria has 4 rows of tables each row has 22 seats. The school patio has 12 tables. Each table seats 4 students. Ho

o-na [289]

Answer:

Here the answer, dearie.

Step-by-step explanation:

$22 \times 4 = 88 \\ 12 \times 4 = 48 \\ 88 + 48 = 136$

So, 136 people can sit in cafeteria and the patio.

6 0

2 years ago

A formula calls for 0.6 mL of a coloring solution. Using a 10-mL graduate calibrated from 2 to 10 mL in 1-mL units, how could yo

MrMuchimi

Answer:

let us add 2.4 mL of water in 0.6 ml of coloring solution

total volume of solution = 2.4 + 0.6 = 3 mL

therefore,

0.6 mL of coloring solution now includes = 2.4ml of water

1 mL of coloring solution includes = 4mL of water

Hence

measure 3 mL of coloring solution with water that is formed

therefore, this 3 mL will contain 0.6 mL of coloring solution

Step-by-step explanation:

Given:

formula calls for 0.6 mL of a coloring solution

10-mL graduate calibrated from 2 to 10 mL in 1-mL units

Now,

We want to use an aliquot technique to measure 0.6 ml of coloring solution.

Because the calibrated graduate is used to measure 2ml to 10ml with 1ml as unit measure

let us add 2.4 mL of water in 0.6 ml of coloring solution

total volume of solution = 2.4 + 0.6 = 3 mL

therefore,

0.6 mL of coloring solution now includes = 2.4ml of water

1 mL of coloring solution includes = 4mL of water

Hence

measure 3 mL of coloring solution with water that is formed

therefore, this 3 mL will contain 0.6 mL of coloring solution

3 0

2 years ago