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IRINA_888 [86]
2 years ago
7

Which graph shows the solution to the equation below log3(x+3)=log0.3(x-1)

Mathematics
2 answers:
algol132 years ago
4 0

Answer: did you get the answer??????

Step-by-step explanation:

Anastasy [175]2 years ago
3 0

Answer:

The answer is a on edg.

Step-by-step explanation:

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Each of 16 students measured the circumference of a tennis ball by four different methods, which were:Method A: Estimate the cir
lys-0071 [83]

Answer:

a) \bar X_A =22.744

\bar X_B =20.7

\bar X_C =21.013

\bar X_D =18.306

b) Median_A =\frac{23+24}{2}=23.5

Median_B =\frac{20.4+20.4}{2}=20.4

Median_C =\frac{21+21}{2}=21

Median_D =\frac{20.7+20.7}{2}=20.7

c) \bar X_A =23.25

\bar X_B =20.7

\bar X_C =21.04

\bar X_D =20.69

Step-by-step explanation:

Data given

Assuming the following data:

Method A: 18.0, 18.0, 18.0, 20.0, 22.0, 22.0, 22.5, 23.0, 24.0,24.0,25.0,25.0, 25.0,25.0,26.0,26.4

Method B: 18.8, 18.9, 18.9, 19.6, 20.1, 20.4, 20.4, 20.4, 20.4,20.5, 21.2. 22.0,22.0, 22.0,22.0,23.6

Method C: 20.2, 20.5, 20.5, 20.7, 20.8, 20.9, 21.0, 21.0,21.0,21.0, 21.0, 21.5,21.5,21.5,21.5,21.6

Method D: 20.0, 20.0, 20.0,-20.0, 20.2, 20.5, 20.5, 20.7, 20.7,20.7, 21.0, 21.1, 21.5, 21.6, 22.1,22.3.

Part a

The sample mean is defined as:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

If we apply this formula for the four methods we got:

\bar X_A =22.744

\bar X_B =20.7

\bar X_C =21.013

\bar X_D =18.306

Part b

Since the total number of points for each method is 16 and this is an even number we need to calculate the median as the average between the 8th and the 9th position of the data ordered from the smallest to the largest. If we do this we have that:

Median_A =\frac{23+24}{2}=23.5

Median_B =\frac{20.4+20.4}{2}=20.4

Median_C =\frac{21+21}{2}=21

Median_D =\frac{20.7+20.7}{2}=20.7

Part c

The trimmed mean by 20% means that we need to calculate removing the 20% from each of the tails, the 20% of 16 is 3.2, so we need to remove 3 observations from both ends of the data like this:

Method A: 20.0, 22.0, 22.0, 22.5, 23.0, 24.0,24.0,25.0,25.0, 25.0

Method B: 19.6, 20.1, 20.4, 20.4, 20.4, 20.4,20.5, 21.2. 22.0,22.0

Method C: 20.7, 20.8, 20.9, 21.0, 21.0,21.0,21.0, 21.0, 21.5,21.5

Method D: 20.0 20.2, 20.5, 20.5, 20.7, 20.7,20.7, 21.0, 21.1, 21.5.

If we calculate the mean for each method we got:

\bar X_A =23.25

\bar X_B =20.7

\bar X_C =21.04

\bar X_D =20.69

3 0
1 year ago
Find the area of the polygon WXYZ with its vertices at W(–3, –2), X(–3, 5), Y(2, 5), and Z(2, –2).
ki77a [65]

Answer:

The area of the polynomial is 35 square unit.

Step-by-step explanation:

It is given that area of the polygon WXYZ with its vertices at W(–3, –2), X(–3, 5), Y(2, 5), and Z(2, –2).

From the below graph it is noticed that the given polynomial is a rectangle with length 5 and width 7.

The distance formula

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the above formula we get,

WX=7

XY=5

YZ=7

WZ=5

The length of opposing sides are equal.

Using the Pythagoras theorem, the length of diagonal WY and XZ are

WY=\sqrt{(WX)^2+(XY)^2}=\sqrt{7^2+5^2}=\sqrt{74}

XZ=\sqrt{(XY)^2+(YZ)^2}=\sqrt{5^2+7^2}=\sqrt{74}

Since the length of the diagonal are same, therefore the given polygon is a rectangle.

The area of a rectangle is

A=l\times w

Where l is length and w is width.

The area of given polynomial is

A=5\times 7

A=35

Therefore the area of the polynomial is 35 square unit.

6 0
2 years ago
Which expression is equivalent to 4√6/3√2
VLD [36.1K]
Given

\frac{4\sqrt{6}}{3\sqrt{2}} = \frac{4\sqrt{2\times3}}{3\sqrt{2}}  \\  \\ = \frac{4\sqrt{2}\sqrt{3}}{3\sqrt{2}} = \frac{4}{3} \sqrt{3}
5 0
2 years ago
Read 2 more answers
Which graph most likely shows a system of equations with no solutions
Vladimir79 [104]

Answer:

The graph attached has a solution. As you can see, the parabolic function DOES intercept the line at (0, 3). Therefore, the solution to that sytem of equation is the point (0, 3).

A system of equations has no solutions when their graphs do NOT meet at any point.

7 0
2 years ago
Read 2 more answers
A surveyor, Toby, measures the distance between two landmarks and the point where he stands. He also measured the angles between
Tju [1.3M]

The Set Up:

x² = (Side1)² + (Side2)² - 2[(Side1)(Side2)]

Solution:

cos(Toby's Angle) • x² = 55² + 65² - 2[(55)(65)] cos(110°)

x² = 3025 + 4225 -7150[cos(110°)]

x² = 7250 - 2445.44x =

√4804.56x = 69.31m

The distance, x, between two landmarks is 69.31m.

Note: The answer choices given are incorrect.

3 0
2 years ago
Read 2 more answers
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