Ask question

Ask question

All categories

2 years ago

15

William and 5 friends each bought 4 baseball cards. They now have a total of 54 cards. How many cards did each person initially

have?

1 answer:

cupoosta [38]2 years ago

5 0

Before buying baseball card they had 34 cards

You might be interested in

A dairy milker's gross pay per week is $546. If she works 30 hours per week, how much does she earn per hour?

loris [4]

$18.20

Explanation:
$546/30hours=$18.20

Plz mark brainiest

8 0

2 years ago

Read 2 more answers

A scatterplot consists of (1, 4.0), (2, 3.3), (3, 3.8), (4, 2.6), and (5, 2.7). The line of best fit used to model the data is y

zhenek [66]

Answer:

b

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

The owners of Prim's Pizza are concerned that many of their customers are starting to purchase pizza from The Pizza Palace becau

AleksandrR [38]

Answer:

$(240-210) -1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=27.953$

$(240-210) +1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=32.047$

And the confidence interval for the difference is between:

$27.953 \leq \mu_1 -\mu_2 \leq 32.047$

Step-by-step explanation:

We have the following info given:

$\bar X_1 = 240$ sample mean for medium Pizzas from Prim's

$\bar X_2 = 210$ sample mean for medium Pizzas from Pizza Place

$s_1 =8.6$ sample deviation for Prim's

$s_2 =5.7$ sample deviation for Pizza Palca

$n_1 =n_2 = 100$ sample size selected for each case

The confidence interval for the difference of means is given by:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

And for the 95% confidence we need a significance level of $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ , the degrees of freedom are given by:

$df= n_1 +n_2 -2= 100+100-2 =98$

And the critical value would be

$t_{\alpha/2}= 1.984$

And replacing we got:

$(240-210) -1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=27.953$

$(240-210) +1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=32.047$

And the confidence interval for the difference is between:

$27.953 \leq \mu_1 -\mu_2 \leq 32.047$

8 0

2 years ago

YOU DONT HAVE TO DO ALL IF YOU DONT WANT TO JUST DO WHAT YOU CAN

Vikki [24]

Answer:

(Warning) Not sure this is completley correct but this is just what I did.

Part A

Does the data for Amit’s puppy show a function? Why or why not?

It does show a function because it passes the vertical line test (no two points have the same x value).

Part B

Is the relationship for Amit’s puppy’s weight in terms of time linear or nonlinear? Explain your response.

Nonlinear because the line isn’t straight

Part C

Is the relationship between Amit’s puppy’s weight in terms of time increasing or decreasing? Explain your response.

Increasing because it is gaining weight

Part D

Does the data for Camille’s puppy show a function? Why or why not?

Yes, it does, because each input value has a unique output value

Part E

Is the relationship for Camille’s puppy’s weight in terms of time linear or nonlinear? Explain your response.

It is a linear function because the line has no curve, and the line is constant.

Part F

Is the relationship between Camille’s puppy’s weight in terms of time increasing or decreasing? Explain your response.

Increasing because as the puppy gets older it gains weight.

Part G

Does the data for Olivia’s puppy show a function? Why or why not?

Yes, it does, because each input value has a unique output value. The graph attached ( which shows the data for Camille’s puppy), that each x-value (Weeks) has a unique y-value (Weight in pounds).

Therefore, based on this and keeping in mind the explanation before, you can conclude that the data for Camille’s puppy shows a function.

Part H

Is the relationship for Olivia’s puppy’s weight in terms of time linear or nonlinear? Explain your response

Yes, it linear because it’s a straight line.

Part I

Is the relationship for Olivia’s puppy’s weight in terms of time increasing or decreasing? Explain your response. Increasing. For every week that goes by, Olivia's puppy is gaining one pound. 6-5= 1 14-13= 1. Gaining a pound every week makes the puppy’s weight increase.

Part J

Which two relationships have a y-intercept and a constant rate of change?

They all have y-intercepts and only Olivia and camilles have a constant rate of change.

Part A

To compare the linear functions, you first need to find their equations. For each of the linear functions, write an equation to represent the puppy’s weight in terms of the number of weeks since the person got the puppy.

Linear equation, y=mx+b

Exponential equation, y=a(b)×

Part B

Now you can compare the functions. In each equation, what do the slope and y-intercept represent in terms of the situation?

The y-intercept in the situation is 2/6.

Part C

Whose puppy weighed the most when the person got it? How much did it weigh?

Olivia’s puppy, it weighed 5 pounds

Part D

Whose puppy gained weight the slowest? How much did it gain per week?

Olivia’s puppy gained weight the slowest because it started off with more weight but only gained around 1 pound every week.

Part E

You can also graph the functions to compare them. Using the Edmentum Graphing Tool, graph the two linear functions. Paste a screenshot of the two functions in the space provided. How could you find which puppy had a greater initial weight from the graph? How could you find which puppy gained weight the slowest?

The edmentum graphing tool is opening up I tried it more than once but, the linear graphs would be Camille puppy and olivia's. And I could tell which one had a greater weight by how much they had at week 1 and how much they gained the weeks later. I could find which puppy gained weight the slowest by looking at the weight gained and graphed.

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

For an F distribution, the number of degrees of freedom for the numerator a. must be larger than the number of degrees of freedo

Alecsey [184]

Answer:

b. can be larger, smaller, or equal to the number of degrees of freedom for the denominator.

Step-by-step explanation:

The distribution of all possible values of the f statistic is called an F distribution with various degree of freedom. For an F distribution, the F statistic is greater than or equal to zero and as the degrees of freedom for the numerator and for the denominator get larger, the curve approximates the normal.

For an F distribution, the number of degrees of freedom for the numerator can be larger, smaller, or equal to the number of degrees of freedom for the denominator.

7 0

2 years ago