Answer:
x₁ > x₂
Step-by-step explanation:
Both actions imply a parable trajectories, since both are projectile shot cases.
Let´s call x₁ maximum distance in the first case
The maximum height is just in the middle of the curve, therefore x₁ the maximum horizontal distance is equal to 60 feet.
In the second case, the parable curve is modeled by:
y = x₂*( 0.08 - 0.002x₂) or y = 0.08*x₂ - 0.002*x₂²
A second degree equation, solving for x₂ and dismissing the value x₂ = 0
we get:
y = 0 ⇒ x₂*( 0.08 - 0.002x₂) = 0 x₂ = 0
And 0,08 - 0.002*x₂ = 0
- 0.002*x₂ = - 0.08
x₂ = 0.08/0.002
x₂ = 40 f
Then x₁ > x₂
For roots of -2, 5, and 7.
x = -2, x = 5, and x = 7
x = -2 x = 5 x = 7
(x + 2) = 0 (x - 5) = 0 (x - 7) = 0
The polynomial of least degree would be:
(x -2)(x - 5)(x - 7) = 0
(x -2)(x -5) = x(x - 5) - 2(x -5)
= x² - 5x - 2x + 10
= x² - 7x + 10
(x² - 7x + 10)(x -7)
x(x² - 7x + 10) - 7(x² - 7x + 10)
x³ - 7x² + 10x - 7x² + 49x - 70
x³ - 7x² - 7x² + 10x + 49x - 70
x³ - 14x² + 59x - 70
The least is x³ - 14x² + 59x - 70
Answer:
So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.
Step-by-step explanation:
The height h of the ball is modeled by the following equation

The problem want you to find the times the ball will be 48 feet above the ground.
It is going to be when:





We can simplify by 16t. So

It means that
16t = 0
t = 0
or
t - 2 = 0
t = 2
So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.
Answer:
20in^2
Step-by-step explanation:
Since you multiply the original area of the triangle by the scale factor to get the new area, you can find the original area (before dilation) by dividing the dilated triangle's area by the scale factor. Since 100 is the area of the dilated triangle, and 5 is your scale factor, you do 100/5 to get the area of the triangle before it was dilated.