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Evgesh-ka [11]
2 years ago
14

A village wishes to measure the quantity of water that is piped to a factory during a typical morning. A gauge on the water line

gives the flow rate (in cubic meters per hour) at any instant. The flow rate is about 120 m3/hr at 6 am and increases steadily to about 280 m3/hr at 9 am. Using only this information, give your best estimate of the total volume of water used by the factory between am and am. Best estimate ____________ m3
Mathematics
1 answer:
nignag [31]2 years ago
4 0
122 is the
answer. i think this help
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The number of cubic feet of water in a curved container can be approximated by v = 0.95h2.9. use a calculator to find the amount
Black_prince [1.1K]
V=0.95h^2.9
h=7.5 feet→V=0.95(7.5)^2.9
V=0.95(344.8876664)
V=327.6432830
Rounded to the nearest tenth:
V=327.6 cubic feet
5 0
2 years ago
Read 2 more answers
Given: ΔABC, AC = BC, AB = 3 CD ⊥ AB, CD = √3 Find: AC
valina [46]

Answer:

\boxed{AC = 2.3}

Step-by-step explanation:

AD = BD  (CD bisects AB means that it divides the line into two equal parts)

So,

AD = BD = AB/2

So,

AD = 3/2

AD = 1.5

<u><em>Now, Finding AC using Pythagorean Theorem:</em></u>

c^2 = a^2+b^2

Where c is hypotenuse (AC), a is base (AD) and b is perpendicular (CD)

AC^2= (1.5)^2+(\sqrt{3} )^2

AC^2 = 2.25 + 3

AC^2 = 5.25

Taking sqrt on both sides

AC = 2.3

3 0
2 years ago
Read 2 more answers
It’s number 13 and I have to use the area formulas to find each missing measure
ivanzaharov [21]
13)
A = bh
h = A/b
h = 211.4  /  24.3
h = 8.7

answer
height = 8.7 m
6 0
2 years ago
Problem 5 (4+4+4=12) We roll two fair 6-sided dice. Each one of the 36 possible outcomes is assumed to be equally likely. 1) Fin
tekilochka [14]

Answer:

1

p(b) =  \frac{1}{6}

2

p(k) =  \frac{1}{3}

3

P(a) =  \frac{1}{3}

Step-by-step explanation:

Generally when two fair 6-sided dice is rolled the doubles are

(1 1) , ( 2 2) , (3 3) , (4 4) , ( 5 5 ), (6 6)

The total outcome of doubles is N = 6

The total outcome of the rolling the two fair 6-sided dice is

n = 36

Generally the probability that doubles (i.e., having an equal number on the two dice) were rolled is mathematically evaluated as

p(b) =  \frac{N}{n}

p(b) =  \frac{6}{36}

p(b) =  \frac{1}{6}

Generally when two fair 6-sided dice is rolled the outcome whose sum is 4 or less is

(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1)

Looking at this outcome we see that there are two doubles present

So

The conditional probability that doubles were rolled is mathematically represented as

p(k) =  \frac{2}{6}

p(k) =  \frac{1}{3}

Generally when two fair 6-sided dice is rolled the number of outcomes that would land on different numbers is L = 30

And the number of outcomes that at least one die is a 1 is W = 10

So

The conditional probability that at least one die is a 1 is mathematically represented as

P(a) =  \frac{W}{L}

=> P(a) =  \frac{10}{30}

=> P(a) =  \frac{1}{3}

3 0
2 years ago
You save $5,000.00 and invest 60% of it in stocks while leaving the rest in a savings account earning a 4.9% APR. The stock incr
Angelina_Jolie [31]

Answer:

5,340

Step-by-step explanation:

Hi there:)

Amount invested in stock

=5000×0.6=3000

Amount invested in a saving account

5000-3000=2000


The stock increases 9% in the first year

3,000×(1+0.09)=3,270

and loses 4% of its value the second year

3,270×(1−0.04)=3,139.2

Amount of a saving account after two years

2,000×(1+0.049)^(2)=2,200.8


the total amount gained during the 2 years

3,139.2+2,200.8=5,340...answer


Hope it helps




8 0
2 years ago
Read 2 more answers
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