The partial factorization of x2 – x – 12 is modeled with algebra tiles. An algebra tile configuration. 4 tiles are in the Factor
1 spot: 1 is labeled + x, 3 are labeled +. 1 tile is in the Factor 2 spot and is labeled + x. 20 tiles are in the Product spot: 1 is labeled + x squared, 3 are labeled + x, the 4 tiles below + x squared are labeled negative x, and the 12 tiles below the + x tiles are labeled negative. Which unit tiles are needed to complete the factorization? 3 negative unit tiles 3 positive unit tiles 4 negative unit tiles 4 positive unit tiles
2 answers:
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Answer:
The number of outfits she purchase with the left money = 3
Step-by-step explanation:
The exact question is as follows :
Given - Nevaeh has $560 to spend at a bicycle store for some new gear and biking outfits. Assume all prices listed include tax. She buys a new bicycle for $383.32. She buys 4 bicycle reflectors for $9.09 each and a pair of bike gloves for $21.07. She plans to spend some or all of the money she has left to buy new biking outfits for $39.75 each.
To find - Write and solve an inequality which can be used to determine x where x, the number of outfits Nevaeh can purchase while staying within her budget.
Proof -
Given that,
Total money Nevaeh have = $ 560
She spent money on bicycle = $ 383.32
She spend money on 1 reflector = $ 9.09
As she buy 4 bicycle reflector, So
Total money spent on bicycle reflector = $ 4×9.09 = $ 36.36
She spend money on a pair of bike gloves = $ 21.07
So,
Total money she spend on the items = $ 383.32 + 36.36 + 21.07
= $ 440.75
⇒Total money she spend on the items = $ 440.75
So,
Total money Left = $ 560 - $ 440.75 = $ 119.25
Now,
She plans to spend some or all of the money she has left to buy new biking outfits for $ 39.75 each.
Let us assume ,
The number of outfits she purchase with the left money = x
AS,
each outfit cost = $ 39.75
So, x outfits cost = $ 39.75 x
Now,
$ 39.75 x = $ 119.25 (because total money left = $ 119.25)
⇒ x = = 3
∴ we get
The number of outfits she purchase with the left money = x = 3
