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AVprozaik [17]
2 years ago
6

A CHICKEN COOP HOLDS A TOTAL OF 10 HENS OR 20 CHICKS. IF 2/5THS OF THE HENS IN A FULL COOP ARE REMOVED, HOW MANY NEW CHICKS COUL

D FIT IN THE CHICKEN COOP?
Mathematics
1 answer:
LiRa [457]2 years ago
5 0

Answer:

8 new chicks can be fitted in the coop.

Step-by-step explanation:

A chicken coop holds 10 hens or 20 chicks.

That means space in the coop for 10 hens = space for 20 chicks

Or space for 1 hen = space for 2 chicks

Now \frac{2}{5}th of the hens were removed from the coop.

So, number of hens removed from the coop = \frac{2}{5}\times 10

= 4 hens

And space for 4 hens in the coop = space for the 8 chicks

Therefore, 8 new chicks can be fitted in the coop.

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John and Belinda played a nine holes of golf. John's score was 10 less than two times Belinda's score. If Johns score was 54 str
polet [3.4K]

Answer:

Belinda's score is 32 strokes.

Step-by-step explanation:

Let the score of John be "x" and Belinda be "y".

It is given that, in the game of golf, John's score was 10 less than two times Belinda's score.

Also, John's score is 54 strokes.

The above equation can be written as ;

x = 2(y) -10

Here, x = 54,

54 = 2(y) -10

64 = 2(y)

y = 32

Thus, Belinda's score is 32 strokes.

6 0
2 years ago
Mr. James has cylindrical beakers that measure 4 inches in diameter and are 9 inches high. What is the volume contained within t
kirill115 [55]
The equation to find the volume of a cylinder is V = pi•r^2•h.
The radius is half of the diameter.  Since Mr. James' beakers have a diameter of 4, their radius would be 2.  2 squared is 4.
Their height is 9 inches.
V = 3.14•4•9
V = 3.14•36
V = 113.04
The answer is C, or 113.04 cubic inches.
5 0
2 years ago
Read 2 more answers
A 747 airplane weighs about 600,000 pounds. It can also be expressed as approximately 3 times 10 Superscript n tons. If there ar
miss Akunina [59]

Answer:

n=2

Step-by-step explanation:

2000 pounds = 1 ton 600000 pounds = X tons Hence X tons = (600000 x 1) ÷ 2000 = 300 tons 3 x 10ⁿ = 300 Hence 3 x 10ⁿ = 3 x 10² Hence n= 2

5 0
2 years ago
Read 2 more answers
A collection of 108 coins containing only quarters and nickels is worth $21. A table titled Coin Collection showing Number of Co
harina [27]

Answer:

q = 108-n

Step-by-step explanation:

Given: 108 coins containing only quarters and nickels

q = 108-n

since total number of coins is 108, and n= number of nickels

If you want to know how many of each kind of coin, read on:

First solve the number of quarters and nickels.

If all 108 coins are quarters, the value is 108*0.25 = $27

Since this value exceed the actual by 27-21 = $6,

we replace a number of quarters by nickels.

Each replacement will reduce the value by 25 - 5 = 20 cents = 0.2 dollars.

So it will take 6/0.2 = 30 replacements.

Therefore there are 108-35 = 78 quarters and 30 nickels.

8 0
1 year ago
Read 2 more answers
Think about all of the ways in which a circle and a parabola can intersect. Select all of the number of ways in which a circle a
forsale [732]

Answer:

A circle can intersect a parabola in

1. One point [ when circle just touches the parabola]

2. Two points [ When circle cuts the parabola in two distinct points. ]

3. Three points [Circle just touches at one point and cuts the parabola in two distinct points]

4. Four points [ Either parabola or circle meeting each other or crossing at four distinct points]




4 0
2 years ago
Read 2 more answers
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