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AVprozaik [17]
2 years ago
6

A CHICKEN COOP HOLDS A TOTAL OF 10 HENS OR 20 CHICKS. IF 2/5THS OF THE HENS IN A FULL COOP ARE REMOVED, HOW MANY NEW CHICKS COUL

D FIT IN THE CHICKEN COOP?
Mathematics
1 answer:
LiRa [457]2 years ago
5 0

Answer:

8 new chicks can be fitted in the coop.

Step-by-step explanation:

A chicken coop holds 10 hens or 20 chicks.

That means space in the coop for 10 hens = space for 20 chicks

Or space for 1 hen = space for 2 chicks

Now \frac{2}{5}th of the hens were removed from the coop.

So, number of hens removed from the coop = \frac{2}{5}\times 10

= 4 hens

And space for 4 hens in the coop = space for the 8 chicks

Therefore, 8 new chicks can be fitted in the coop.

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Step-by-step explanation:

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2 years ago
Share 747 pounds in the ratio 2:7 between tom and ben
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Ted is a long distance driver. It took him 30 min longer to drive 275km on the Trans-Canada highway west of Swift Current, Saska
IRISSAK [1]

Speed traveling west = x - 10 km /hr


275 / ( x-10) - 300 / x = 1/2



275 *2x - 300 (x-10)*2 = ( x-10) *x



550x - 600x +6000 = x^2 -10x



x^2 +40x - 6000 = 0


( x -60) ( x+100) = 0


x = 60


ANSWER East = 60 km/ hr West = 50 km /hr


CHECK


300 /60 = 5 hours

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7 0
2 years ago
Using two or more complete sentences, describe how to find the general rule for the arithmetic sequence with a4 = -1 and a6 = -1
adoni [48]

Answer:

Step-by-step explanation:

to find the arithmetic sequence with a4=-1 and a6=-13

first: find the difference: an=a+(n-1)d

a4=-1

that means a1+d(4-1)=-1 ( since a4 given and need to find a1)

a1+3d=-1 first equation

a1+d(6-1)=-13 ( a6 is given)

a1+5d=-13 second equation

a1+3d=-1

a1+5d=-13 ( find a and d by subtraction)

a1+3d-a1-5d=-1-(-13)

2d=12

d=-12/2=-6 ( substitute d in the equation: a1+3d=-1)

difference =-6

a1=17

a1,a2,a3,a4,a5,a6,....

the sequence is : 17,11,5,-1,-7,-13,.....

hope it works

5 0
2 years ago
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