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Aleks04 [339]
2 years ago
3

A student is constructing a triangle with the following dimensions: side length of 10 inches side length of 30 inches Which meas

urements could be the length of the third side? Select all that apply. 19 inches 21 inches 35 inches 45 inches 50 inches
Mathematics
2 answers:
frosja888 [35]2 years ago
3 0

Answer:

21 and 35

Step-by-step explanation:

I took the test and I got it right

have a good day

ella [17]2 years ago
3 0

Answer:

21 and 35 inches

Step-by-step explanation: just did it

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We need to find the expression for " number_of_prizes is divisible number_of_participants". Also there should not remain any remainder left. On in order words, we can say the reaminder we get after division is 0.

Let us assume number of Prizes are = p and

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If we divide number of Prizes by number of participants and there will be not remainder then there would be some quotient remaining and that quotent would be a whole number.

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So, we can setup an expression now.

Let us rephrase the statement .

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p ÷ n = q.

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True or False: The value of r represents the reference angle when plotting a point in polar coordinates.
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Evaluate ∫SF⃗ ⋅dA⃗ , where F⃗ =(bx/a)i⃗ +(ay/b)j⃗ and S is the elliptic cylinder oriented away from the z-axis, and given by x2/
Norma-Jean [14]

Answer:

Therefore surface integral is \pi(a^2+b^2)c-0-0=\pi(a^2+b^2)c.

Step-by-step explanation:

Given function is,

\vec{F}=\frac{bx}{a}\uvec{i}+\frac{ay}{b}\uvec{j}

To find,

\int\int_{S}\vec{F}dS  

where S=A=surfece of elliptic cylinder we have to apply Divergence theorem so that,

\int\int_{S}\vec{F}dS

=\int\int\int_V\nabla.\vec{F}dV

=\int\int\int_V(\frac{b}{a}+\frac{a}{b})dV  

=\frac{a^2+b^2}{ab}\int\int\int_VdV

=\frac{a^2+b^2}{ab}\times \textit{Volume of the elliptic cylinder}

=\frac{a^2+b^2}{ab}\times \pi ab\times 2c=\pi (a^2+b^2)c

  • If unit vector \cap{n} directed in positive (outward) direction then z=c and,

\int\int_{S_1}\vex{F}.dS_1=\int\int_{S_1} . dA      

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  • If unit vector \cap{n} directed in negative (inward) direction then z=-c and,

\int\int_{S_2}\vex{F}.dS_2=\int\int_{S_2}. -dA      

=\int\int_{S_2}. -dA=0

Therefore surface integral without unit vector of the surface is,

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Answer:

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Step-by-step explanation:

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