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padilas [110]
2 years ago
15

Circle T has diameters RP and QS. The measure of ∠RTQ is 12° less than the measure of ∠RTS.

Mathematics
2 answers:
Olenka [21]2 years ago
7 0

The measure of Arc Q P is 96°. We also know that ∠QTP is central angle, then the measure of arc QP is 96°.

Step-by-step explanation:

<u>Step 1</u>

If QS is a circle diameter,

then m∠QTS=180°.

Let x be the measure of angle RTQ: ∠RTQ =x.

so, let ∠RTQ = x

<u />

<u>Step 2</u>

According to the question,

∠RTQ = ∠RTS - 12°

⇒ ∠RTS = x + 12°

∴ ∠QTS = ∠RTQ + ∠RTS

= x + x + 12° = 2x + 12° = 180°

⇒ 2x = 168°

⇒ x = 84°

⇒ ∠RTQ = 84°

<u></u>

<u>Step 3</u>

Now,

∵∠QTP and ∠RTS are vertical angles

∴ ∠QTP = 84° + 12° = 96°

As ∠QTP is the central angle, hence the measure of arc QP is 96°

<u></u>

<u>Step 4</u>

The Measure of arc QP = 96°

Lena [83]2 years ago
4 0

Answer: 96 is the answer

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2 years ago
HELP PLEASE. A pizza shop charges customers based on the area of the pizza they order. The cost of a pizza in dollars can be rep
san4es73 [151]

For this case we have that the cost of each pizza is given by the following function:

S (r) = 0.1 \pi * r ^ 2

Where:

r: It's the radius of the pizza

IF a pizza cost $26.32 we have:

26.32 = 0.1 \pi * r ^ 2

We cleared the radius, using \pi = 3.14:

\frac {26.32} {0.1} = \pi * r ^ 2\\263.2 = 3.14r ^ 2\\\frac {263.2} {3.14} = r ^ 2\\83.82 = r ^ 2\\r = \pm \sqrt {83.82}

We choose the positive value:

r = 9.15

So, the radius of the pizza is 9.16 \ in

Then, the diameter is: 2r = 2 * 9.15 = 18.30 \ in

Finally, the diameter of the pizza is:18.30 \ in

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Option B

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2 years ago
Read 2 more answers
The function f(x) = 1/2 x + 3/2 is used to complete this table.
Mrac [35]

Answer:

a) f(-1/2)  = -2 is NOT TRUE.

b)  f(0)  =3/2 is  TRUE.

c)   f(1)  = -1 is NOT TRUE.

d)   f(2)  = 1 is NOT TRUE.

e)   f(4)  = 7/2  is  TRUE.

Step-by-step explanation:

Here, the given function is  f(x) = (\frac{1}{2}) x+\frac{3}{2}

Now, checking for each values for the given function:

a) Putting x  = (-1/2):

 f(\frac{-1}{2} ) = (\frac{1}{2})(\frac{-1}{2} ) +\frac{3}{2}   = \frac{-1}{4}  + (\frac{3}{2} )\\\implies f(x) = \frac{-1 + 6}{4}  = (\frac{5}{4} )

and (5/4) ≠  -2

Hence, f(-1/2)  = -2 is NOT TRUE.

b)Putting x  = 0 :

f(0) = (\frac{1}{2})(0 ) +\frac{3}{2} = (\frac{3}{2} )

Hence, f(0)  =3/2 is  TRUE.

c) Putting x  = 1:

f(1 ) = (\frac{1}{2})(1 ) +\frac{3}{2}   = \frac{1}{2}  + (\frac{3}{2} )\\\implies f(x) = \frac{3 + 1}{2}  = (\frac{4}{2} )   = 2\implies 2   \neq -1

Hence, f(1)  = -1 is NOT TRUE.

d)Putting x  = 2:  

f(2 ) = (\frac{1}{2})(2 ) +\frac{3}{2}   = 1+ (\frac{3}{2} )\\\implies f(x) = \frac{2 + 3}{2}  = (\frac{5}{2} )

and (5/2) ≠  1

Hence, f(2)  = 1 is NOT TRUE.

e)Putting x  = 4:

 f(4 ) = (\frac{1}{2})(4 ) +\frac{3}{2}   = 2  + (\frac{3}{2} )\\\implies f(x) = \frac{4 + 3}{2}  = (\frac{7}{2} )

Hence, f(4)  = 7/2  is  TRUE.

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Answer:

x = (-29)/5

Step-by-step explanation:

Solve for x:

(2 (x - 5))/3 = (3 (x + 1))/2

Multiply both sides by 6:

(6×2 (x - 5))/3 = (6×3 (x + 1))/2

6/3 = (3×2)/3 = 2:

2×2 (x - 5) = (6×3 (x + 1))/2

6/2 = (2×3)/2 = 3:

2×2 (x - 5) = 3×3 (x + 1)

2×2 = 4:

4 (x - 5) = 3×3 (x + 1)

3×3 = 9:

4 (x - 5) = 9 (x + 1)

Expand out terms of the left hand side:

4 x - 20 = 9 (x + 1)

Expand out terms of the right hand side:

4 x - 20 = 9 x + 9

Subtract 9 x from both sides:

(4 x - 9 x) - 20 = (9 x - 9 x) + 9

4 x - 9 x = -5 x:

-5 x - 20 = (9 x - 9 x) + 9

9 x - 9 x = 0:

-5 x - 20 = 9

Add 20 to both sides:

(20 - 20) - 5 x = 20 + 9

20 - 20 = 0:

-5 x = 9 + 20

9 + 20 = 29:

-5 x = 29

Divide both sides of -5 x = 29 by -5:

(-5 x)/(-5) = 29/(-5)

(-5)/(-5) = 1:

x = 29/(-5)

Multiply numerator and denominator of 29/(-5) by -1:

Answer: x = (-29)/5

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