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valina [46]
2 years ago
14

Find the exact value of tan 7pi/6

Mathematics
1 answer:
sergeinik [125]2 years ago
4 0

Answer:

\sqrt{3} /3 or 210°

Step-by-step explanation:

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Bob's bill for dinner at surefire steak house was $45. In addition he piad 5°\° of the bill in tax and he left a tip for 15°\° o
Anuta_ua [19.1K]

Answer:

$54

Step-by-step explanation:

First

45 times .05= 2.25

Second

45 plus 2.25

Third

45 times .15= 6.75

Fourth

45+2.25+6.75

5 0
2 years ago
Solve the system of equations.<br> - 5x + 2y = 9
Marina CMI [18]

Answer: -5x + 2y -9 = 0

Step-by-step explanation:

1. Move constant to the left and change its sign

2. Change the signs on both sides of the equation

3 0
2 years ago
11. A basketball team of 16 players consists of 6 guards, 7 forwards, and 3 centers. The coach decides to randomly select 5 play
Citrus2011 [14]

Answer:

0.2163

Step-by-step explanation:

Firstly, we need to evaluate the total number of possible outcomes. Since there are 16 players, and we are selecting just 5, the total number of possibilities is 16C5= 4,368

Now, we know we need 2 guards from 6 , 2 forwards from 7 and 1 center from 3 to start the game. Since we are selecting, it is a combination problem. These can be done in the following number of ways:

6C2 * 7C2* 3C1

The probability is thus (6C2 * 7C2* 3C1 )/16C5 = 945/4368 = 0.2163

8 0
2 years ago
Which of the following is being constructed in the image?
madam [21]
The answer is C, a perpedicular bisector. The distances of the mark along the given line are equidistance. Where the x is located, where the two dashes would intersect is where a 90 degre angle to the line would pass through. 
5 0
2 years ago
Read 2 more answers
The 8th term of a GP is -7/32 find its common ratio if its first term is 28
Ugo [173]
<h2>Common ratio = -1/2</h2>

Step-by-step explanation:

       \text{8}^{th} term of a Geometric progression is given as \dfrac{-7}{32}. The first term is given as 28.

       Any general Geometric progression can be represented using the series a,ar,ar^{2},ar^{3},ar^{4}...\text{ }ar^{n-1}.

The first term in such a GP is given by a, common ratio by r, and the n^{th} term is given by ar^{n-1}.

       In the given GP, a=28;t_{8}=ar^{7}=\dfrac{-7}{32}\\\\28r^{7}=\dfrac{-7}{32}\\\\r^{7}=\dfrac{-1}{128}\\\\r=\dfrac{-1}{2}

∴ Common ratio is \dfrac{-1}{2}.

5 0
2 years ago
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