Which of the following expenses are typically paid by credit?

There is a harvest festival each year on the planet Bozone. During that time, most of the Bozone residents sit down to rejoice a

Oliga [24]

Answer:

The price would be decreased by 18 bozats

Step-by-step explanation:

The following information is given in the question

x = number of kilograms of snig sold

P = Price per kilogram

And, the equation is

p = 300 - 18x

Now if an extra kilogram is sold so it should be x+1

Now the new price is

New price = 300 - 18(x + 1)

= 300 - 18x - 18

Therefore the price would be decreased by 18 bozats

8 0

2 years ago

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Marissa is ordering Negative one-sixth, negative one-third, 1.4, 0.2, two-thirds from least to greatest. Here are her steps:

Effectus [21]

Step-by-step explanation:

no 2

if wrong correct me pls

6 0

2 years ago

What is the ratio of the area of sector ABC to the area of sector DBE?

shusha [124]

We have to find the" ratio of the area of sector ABC to the area of sector DBE".

Now,

the general formula for the area of sector is

Area of sector= 1/2 r²θ

where r is the radius and θ is the central angle in radian.

180°= π rad

1° = π/180 rad

For sector ABC, area= 1/2 (2r)²(β°)

= 1/2 *4r²*(π/180 β)

= 2r²(π/180 β)

For sector DBE, area= 1/2 (r)²(3β°)

= 1/2 *r²*3(π/180 β)

= 3/2 r²(π/180 β)

Now ratio,

Area of sector ABC/Area of sector DBE = $\frac{2r^{2}*\ \frac{\pi}{180} beta}{3/2 r^{2}*\ \frac{\pi}{180}beta}$

= 4/3

7 0

2 years ago

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Mikela claims that the sum of any two numbers is greater than the larger of the two numbers. Jim claims that the sum of any two

qaws [65]

<u>ANSWER: </u>

The statement of Jim is correct

<u>SOLUTION: </u>

Given statements are

Mikela claims that sum of any two numbers is greater than the larger of the two numbers.

Jim claims that the sum of any two natural numbers is greater than the larger of the two numbers.

Let a,b be the two numbers and a is the greatest of a and b

According to the mikela statement = a + b > a

b > a – a

b > 0

Here, we got an condition that b > 0, but it may not be true always.

Above condition fails when b is either 0 or negative number.

Jim - sum of any two natural numbers is greater than the larger of the two numbers.

Let a,b be the two natural numbers. And a is the greatest of a and b

According to the jim statement = a + b > a

b > a – a

b > 0

Here, we got an condition that b > 0,

And this statement will always be true because b is an natural number, so it will be greater than 0.

Hence jim’s statement is true.

8 0

2 years ago

The parallel dotplots below display the girths (belly

liraira [26]

Answer:

The standard deviation for the distribution of girths is

about the same for both male and female pigs.

Step-by-step explanation:

Step 1

We will interprete the dotplots

For the Male pigs

24, 26, 26, 26, 26, 26, 26, 28, 28, 28, 28, 28, 28, 28, 28, 28, 28, 28, 30, 30, 30, 30, 30, 30, 32

Range

Maximum value - Minimum value

= 32 - 24

= 8

IQR = Interquartile range = Q3 - Q1

Q1 formula = 1/4(n + 1)th

=n = 25

= 1/4(25 + 1)

= 1/4(26)

= 26/4

= 6.5

This mean the value is between the 6th and 7th value

6th value = 26

7th value = 26

Q1 = 26 + 26/2

Q1 = 26

Q3

Q3 formula = 3/4(n + 1)th

=n = 25

= 3/4(25 + 1)

= 3/4(26)

= 78/4

= 19.5

This mean the value is between the 19th and 20th value

19th value = 30

20th value = 30

Q3= 30+ 30/2

= 30

IQR = 30 - 26

= 4

Standard deviation

Mean

First we find the mean

= 24+ 26+26+ 26+ 26+ 26+26+28+ 28+ 28+ 28+28+ 28+ 28+28+ 28+28+28+30+ 30+30+ 30+30+30+32/28

= 700/25

= 28

Standard deviation Formula = √(x - mean)²/n - 1

= √[(24-28)² + (26- 28)² + (26 -28)² + (26 - 28)² +................ (32 - 28)²]/25 - 1

= √(16 + 4 + 4+ 4+ 4+4+ 4+0+ 0+ 0+ 0+0+ 0+ 0+ 0+0+0+0+ 4+ 4+4+4+4+ 4+ 16)/25 - 1

= √80/25 - 1

=√3.333333333

1.825741858

Female Pigs

21, 23, 23, 23,23,23,23,25, 25, 25, 25, 25, 25, 25, 25, 25, 25,25, 27, 27, 27, 27,27, 27, 29

Range:

Maximum value - Minimum value

= 29 - 21

8

IQR

IQR = Interquartile range = Q3 - Q1

Q1 formula = 1/4(n + 1)th

=n = 25

= 1/4(25 + 1)

= 1/4(26)

= 26/4

= 6.5

This mean the value is between the 6th and 7th value

6th value = 23

7th value = 23

Q1 = 23 + 23/2

Q1 = 23

Q3

Q3 formula = 3/4(n + 1)th

=n = 25

= 3/4(25 + 1)

= 3/4(26)

= 78/4

= 19.5

This mean the value is between the 19th and 20th value

19th value = 27

20th value = 27

Q3= 27+ 27/2

Q3 = 27

IQR = 27 - 23

= 4

First we find the Mean

=(21+23+23+23+23+23+23+25+ 25+ 25+ 25+25+ 25+ 25+ 25+25+25+25+27+27+ 27+27+27+ 27+29)/25

= 625/25

= 25

Standard deviation Formula = √(x - mean)²/n - 1

= √[(21-25)² + (23- 25)² + (23 -25)² + (23 - 25)² +................ (29 - 25)²]/25 - 1

= √(16 + 4 + 4+ 4+ 4+4+ 4+0+ 0+ 0+ 0+0+ 0+ 0+ 0+0+0+0+ 4+ 4+4+4+4+ 4+ 16)/25 - 1

= √80/25 - 1

=√3.333333333

1.825741858

Looking at the calculation above and comparing both the girths from the male and female

We can conclude that: The standard deviation for the distribution of girths is

about the same for both male and female pigs which is 1.825741858

5 0

2 years ago