There is many ways to do this but i did it this way.
180-123.75= 56.25
56.25/5=11.25
=11.25
Answer:
Step-by-step explanation:
a.) The worst-case height of an AVL tree or red-black tree with 100,000 entries is 2 log 100, 000.
b.) A (2, 4) tree storing these same number of entries would have a worst-case height of log 100, 000.
c.) A red-black tree with 100,000 entries is 2 log 100, 000
d.) The worst-case height of T is 100,000.
e.) A binary search tree storing such a set would have a worst-case height of 100,000.
This bill is about 4.21 standard deviations below the mean value.
To find this, first subtract the mean from the given amount.
30 - 64.5 = -34.5
Now, divide this by 8.2, which is the amount of 1 standard deviation.
34.5 / 8.2 = 4.21
Answer:
Yes
Step-by-step explanation:
If you have any questions about the way I solved it,don't hesitate to ask
Glad to help
Scale factor is 9/15 or 3/5 in simplest form, and I think x would equal 10.
