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Maurinko [17]
2 years ago
15

You are faced with the probability distribution of the HPR on the stock market index fund given in Spreadsheet 5.1 of the text.

Suppose the price of a put option on a share of the index fund with exercise price of $110 and time to expiration of 1 year is $12, and suppose the risk-free interest rate is 6% per year. You are contemplating investing $107.55 in a 1-year CD and simultaneously buying a call option on the stock market index fund with an exercise price of $110 and expiration of 1 year.
Business
1 answer:
Dima020 [189]2 years ago
5 0

Answer:

Answer = $114

Explanation:

We are investing $107.55 in CD for 1 year with the risk free rate of 6% per annum.

So, at the end of 1 year we will receive the face value as well as the interest on the same.

So, ending value of CD = 107.55*1.06 (6% interest) = $114.003

= $114

Now, in case of the excellent economic conditions, the ending price of stock is $131. So, here instead of buying the stock from market we will exercise our call option at the rate of $110.

So, value of our call will be:-

Probability * Ending value of CD - cost of call option

= 0.25*114 - 12

= $16.5

So, combined value will be $130.5 (114 + 16.5) which is less than the market price of $131.

In all the other three cases, the end price of stock is less than the ending value of CD. So, instead of exercising the call option, we will purchase the stock from market at less price to make profits.

So, combined value in the other three cases will be the ending value of CD = $114.

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swenson Saws produces bows, frame, dovetail, and tenon saws used by craft furniture makers. During an 8-hour shift, a saw is pro
RUDIKE [14]

Answer:

Given: Total shift time = 8 hours = 8 * 60 = 480 minutes

time required for production of one saw = 6 minutes

Demand for Bow saw = Demand for frame saw = Demand for dovetail saw = 1/2 * Demand of Tenon saw

a) Mixed model schedule:

Mixed model schedule

Product no. per batch

Bow Saw 1

Frame Saw 1

Dovetail Saw 1

Tenon Saw 2

Total 5

Therefore 2 Tenon Saw, and each bow, frame, and dovetail saws will be produced before the cycle is repeated.

b) 2 Tenon Saw, 1 bow, 1 frame, and 1 dovetail saws will be produced under production sequence for one unit production.

The length of cycle will be 5*6=30 minutes i.e. the cycle will repeat once in 30 minutes for 8 hours means totally it will repeat 16 times during one shift.

c) Number of saws Swenson produce in one shift = Number of Bow saw Swenson produce in one shift + Number of Frame saw Swenson produce in one shift + Number of Dovetail saw Swenson produce in one shift + Number of Tenon saw Swenson produce in one shift

Explanation:

7 0
1 year ago
Read 2 more answers
Assume that the demand for tuna in a small coastal town is given by p = 400,000 q1.5 , where q is the number of pounds of tuna t
oee [108]

Answer:

(a) p = $ per lb

p = $2.12 per lb

(b) q = lb (c)

q = $23320

Explanation:

p=750000/q^1.5=>

p'=-1125000q^(-2.5)<0 always

=>p is decreasing with the  

increasing of q. So q should take

the allowable least value=5000.

=>

(a) the charge=  750000/(5000)^1.5=  $2.12/lb

(b)The max. revenue=

q = lb (c) = 2.12(5000)=  $23320

3 0
2 years ago
Using the intuitive least cost method for the given transportation problem, answer the following: Cleveland Dayton Erie Supply A
ch4aika [34]

Answer:

The demand location where demand is unmet is equal to Cleveland. Received only 75 units. 100 units demand is unmet.

Explanation:

Solution

From the example given, we solve for which demand location will have an unmet demand

Now,

The maximum quantity that can be shipped from Allentown to Erie is 100.

The Maximum quantity that can be shipped from Harrisburg to Cleveland is 175

While,

The Maximum quantity that can be shipped from Harrisburg to Dayton is 175

Hence, in case we want an  solution optimum to get the required demand as many as possible with the supply given and with a low costs, then we need to find the optimum solution.

By applying a least cost method called greedy, we need to remove our least costing node and then provide minimum of demand and supply unit a present to each cell.

Thus,

The first least cost is Allentown to Dayton.

From Allentown to Dayton 100 units. Next least cost is Philadelphia to Erie.

From Philadelphia to Erie 150 units. Next least cost is Harrisburg to Erie.

From Harrisburg to Erie 25 units. Next least cost is Harrisburg to Dayton.

From Harrisburg to Dayton 75 units. Next least cost is Harrisburg to Cleveland

From Harrisburg to Cleveland 75 units.

So, for the  optimum solution, the right choice of answer will be

From Allentown to Erie = 0 units

From Harrisburg to Cleveland = 75 units

From Harrisburg to Dayton = 75 units

Therefore, The demand location where demand is unmet  is equal to Cleveland. Received only 75 units. 100 units demand is unmet.

6 0
2 years ago
The constraint at Pickrel Corporation is time on a particular machine. The company makes three products that use this machine. D
rosijanka [135]

Answer:

JT, SM, VD

Explanation:

Calculation to rank the products in the order in which they should be emphasized

VD JT SM

Selling price per unit

$ 344.85 $ 415.40 $ 119.32

Less:Variable cost per unit

$ 270.18 $ 310.88 $ 91.96

Contribution per unit

$74.67 $104.52 $27.36

÷Minutes on the constraint 5.70 6.70 1.90

=Contribution per minut

$13.10 $15.60 $14.40

Ranking

VD $13.10 Third

JT $15.60 First

SM $14.40 Second

JT, SM, VD

Therefore the product will be rank from the highest to the lowest which is JT, SM, VD

5 0
1 year ago
Cash Short and Over Entries 1. Based on the information, prepare the weekly entries for cash receipts from service fees and cash
Harrizon [31]

Answer:

Explanation:

The journal entries are shown below:

On April 2

Cash A/c Dr $266.50

Cash short and over A/c Dr $2

            To service fees revenue A/c $268.50

(Being service fees revenue is recorded)

On April 9

Cash A/c Dr $233.50

Cash short and over A/c Dr $4.25

            To service fees revenue A/c $237.50

(Being service fees revenue is recorded)

On April 16

Cash A/c Dr $311.00

            To Cash short and over A/c Dr $1.75

            To service fees revenue A/c $309.25

(Being service fees revenue is recorded)

On April 23

Cash A/c Dr $224.00

Cash short and over A/c Dr $2.50

            To service fees revenue A/c $226.50

(Being service fees revenue is recorded)

On April 30

Cash A/c Dr $322.00

            To Cash short and over A/c Dr $4.00

            To service fees revenue A/c $318.00

(Being service fees revenue is recorded)

4 0
2 years ago
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