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larisa [96]
2 years ago
4

Brandon works at a small petting zoo with 888 animals. He was looking at some data showing the masses of the animals. Each anima

l had a different mass between 222 and 160\,\text{kg}160kg160, start text, k, g, end text. The zoo then buys a horse that weighs 900\,\text{kg}900kg900, start text, k, g, end text as their 9^{\text{th}}9 th 9, start superscript, start text, t, h, end text, end superscript animal. [Show data] 22 33 55 77 2727 3636 4545 160160 900900 How does buying the horse affect the mean and median? Choose 1 answer: Choose 1 answer: (Choice A) A Both the mean and median will increase, but the median will increase by more than the mean. (Choice B) B Both the mean and median will increase, but the mean will increase by more than the median. (Choice C) C Both the mean and median will decrease, but the median will decrease by more than the mean. (Choice D) D Both the mean and median will decrease, but the mean will decrease by more than the median.
Mathematics
1 answer:
Lunna [17]2 years ago
6 0

Answer:

B Both the mean and median will increase, but the mean will increase by more than the median

Step-by-step explanation:

<u>Revised question</u>

Brandon works at a small petting zoo with 8 animals. He was looking at some data showing the masses of the animals. Each animal had a different mass between 2 and 160 kg. The zoo then buys a horse that weighs 900 kg as their 9th animal.

Animal Weight (in kilograms)

  • chicken 2
  • duck 3
  • goose 5
  • barn cat 7
  • dog 27
  • goat 36
  • lamb 45
  • pig 160
  • horse 900

==================

<h3>Solution</h3>

Data ordered

  • 2, 3, 5, 7, 27, 36, 45, 160

Mean

  • (2+3+5+7+27+36+45+160)/8 = 35.625

Median, average of middle terms as even data:

  • (7+27)/2 = 17
<h3>Horse added</h3>

<u>Mean has increased significantly</u>

  • (2+3+5+7+27+36+45+160+900)/9 = 131.667

<u>Median </u>

  • moved to right and become 27 since number become odd

<u>Based on above we can say that:</u>

  • Both the mean and median will increase, but the mean will increase by more than the median
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