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Veronika [31]
2 years ago
12

When wiring a house, an electrician knows that the time she will take is given by the formula

Mathematics
2 answers:
lbvjy [14]2 years ago
5 0
Answer: 395

CALL OUT FEE= 35
30 PER HOUR= 2 HOURS TO BE=60
BUT, 12 MINUTES IN HOURS = 12/60 = 0.2
0.2 = 0.2*30 =6
2 HOURS AND 12 MINUTES WOULD BE CHARGED AS
30+6 = 36
36*10=360
CALL OUT FEE+ PER HOUR = 35 + 360= 395
lyudmila [28]2 years ago
4 0

Answer:

£155

Step-by-step explanation:

look at the formula

first solve 12 minutes per light switches

12*10(lightswitches)= 120 minutes

we know that 120 minutes = 2 hours

the task says that she charges £30 per hour

so, 2 hours+ 2 hours= 4 hours

now do

4*30= £120

120+35(call-out fee)= £155

I really hope this helped.

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Essa pergunta nao esta em forma ingles, então pessoas nao vao entender.

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Sin(11∘)cos(19∘)+cos(11∘)sin(19∘)
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Gary's salary varies directly as the number of days he works. If his salary for five days is $52.00, how much would it be for 12
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Answer:

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8 0
1 year ago
A bin of 5 transistors is known to contain 2 that are defective. The transistors are to be tested, one at a time, until the defe
xxMikexx [17]

Answer:

P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}

Step-by-step explanation:

For the random variable N_1 we define the possible values for this variable on this case [1,2,3,4,5] . We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:

5C2 = \frac{5!}{2! (5-2)!}= \frac{5*4*3!}{2! 3!}= \frac{5*4}{2*1}=10

We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable N_1 like this:

P(N_1 = a) = \frac{5-a C 1}{5C2}

For the distribution of N_2 we need to take in count that we are finding a conditional distribution. N_2 given N_1 =a, for this case we see that N_2 \in [1,2,...,5-a], so then exist 5-a C 1 ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:

P(N_2 =b | N_1 = a) = \frac{1}{5-a C 1}

And if we want to find the joint probability we just need to do this:

P(N_1 = a , N_2 = b) = P(N_2 = b | N_1 = a) P(N_1 =a)

And if we multiply the probabilities founded we got:

P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}

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A boat is traveling east across a river that is 112 meters wide at 8 meters per second. If the river has a northward current of
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6 0
2 years ago
Read 2 more answers
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