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grin007 [14]
2 years ago
9

Which ratio is also equal to StartFraction R T Over R X EndFraction and StartFraction R S Over R Y EndFraction? StartFraction X

Y Over T S EndFraction StartFraction S Y Over R Y EndFraction StartFraction R X Over X T EndFraction StartFraction S T Over Y X EndFraction

Mathematics
2 answers:
serg [7]2 years ago
6 0

Answer:

D

Step-by-step explanation:

jekas [21]2 years ago
5 0

Answer:

△RST ~ △RYX by the SSS similarity theorem. Which ratio is also equal to RT/RX and RS/RY ?

A.XY/TS

B.SY/RY

C.RX/XT

D.ST/YX

Step-by-step explanation:

Check attachment for solution

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Referring to the scale, 1:50 what is the actual measurement of the wall marked 18 cm on the plan?
vfiekz [6]

Answer:

900 cm

Step-by-step explanation:

1 : 50

We need the first number to be 18 so multiply by 18

1:18 : 50*18

18 cm : 900 cm

4 0
2 years ago
Arnold took out a loan of 195,000 to purchase a home. At a 4.3% interest rate compounded annually, how much total will they have
kolbaska11 [484]

Answer:

25155000

Step-by-step explanation:

<h3>we know intrest (i):-PTR/100</h3>

by formula

  1. <u>195000×30×4.3%</u>

100

2. 5850000<u>×4.3</u>

<u>100</u>

100

3. 25155000

3 0
2 years ago
Ariel left her home at 9 a.m., driving at 45 mph. At 11 a.m. her brother left the home and started after her at 60 mph. At what
Vlada [557]

Answer:

5:00 pm

Step-by-step explanation:

Let

x -----> the umber of hours

y ----> the total distance in miles

we know that

The distance is equal to the speed multiplied by the time

Find out the distance traveled by Ariel at 11:00 am

11:00 am-09:00 am=2 hours

45(2)=90 miles

so

<em>Ariel's linear equation is</em>

y=45x+90 ----> equation A

<em>Ariel's brother linear equation is</em>

y=60x ----> equation B

Equate equation A and equation B

60x=45x+90

Solve for x

60x-45x=90

15x=90

x=6\ hours

Adds 11:00 am + 6 hours=17:00 =5:00 pm

6 0
2 years ago
Byron’s income last year was $61,700. He made $48,000 at his plumbing job and had income from an apartment that he rented out. I
Alika [10]
$1141.67
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5 0
2 years ago
Read 2 more answers
Suppose the time required for an auto shop to do a tune-up is normally distributed, with a mean of 102 minutes and a standard de
hammer [34]

Answer:

Step-by-step explanation:

Suppose the time required for an auto shop to do a tune-up is normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - u)/s

Where

x = points scored by students

u = mean time

s = standard deviation

From the information given,

u = 102 minutes

s = 18 minutes

1) We want to find the probability that a tune-up will take more than 2hrs. It is expressed as

P(x > 120 minutes) = 1 - P(x ≤ 120)

For x = 120

z = (120 - 102)/18 = 1

Looking at the normal distribution table, the probability corresponding to the z score is 0.8413

P(x > 120) = 1 - 0.8413 = 0.1587

2) We want to find the probability that a tune-up will take lesser than 66 minutes. It is expressed as

P(x < 66 minutes)

For x = 66

z = (66 - 102)/18 = - 2

Looking at the normal distribution table, the probability corresponding to the z score is 0.02275

P(x < 66 minutes) = 0.02275

4 0
2 years ago
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