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2 years ago

Find the perimeter of the figure to nearest hundredth 20mm, 20mm, 16mm

Mathematics

1 answer:

bearhunter [10]2 years ago

8 0

Answer:

The perimeter is 56mm

Step-by-step explanation:

N/B: the figure is not given, nevertheless we can infer that the figure is a triangular figure given that the lengths provided is just three.

So the perimeter is the distance around the object.

Perimeter =20+20+16= 56mm

Also see attached a rough sketch for your reference.

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What is the time period of a loan for $2,500 at 12% exact interest if the amount of interest is $118.36? Round to the next highe

Marianna [84]

I believe it's 144 days.

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Three snack bars contain 1/5, 0.22, and 19% of their calories from fat. Which snack bar contains the least amount of calories fr

BabaBlast [244]

Converting all values to decimal, we have
1/5 = 0.2
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2 years ago

PQ= 2x +1 and QR= 5x - 44; find PQ

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2x+1=5x-44 that would be your equation

next start to simplify

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21. Randy owns a computer store. In 1990, he sold 150 monitors. In 2000, he sold 900

lutik1710 [3]

Answer:

$y=75x+150$

Step-by-step explanation:

Let $y$ represent the number of monitors sold.

Given:

$x$ is the number of years since 1990.

So, for the year 1990, $x=0$ .

For the year 2000, 10 years passed. So, $x=10$ .

Now, monitors sold in 1990 are 150. So, at $x=0,y=150$

Monitors sold in 2000 are 900. So, at $x=10,y=900$

Thus, the two points are $(0,150)$ and $(10,900)$ .

The slope of a line with points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is given as:

Slope, $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

For the points $(0,150)$ and $(10,900)$ , the slope is given as:

Slope, $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\ m=\frac{900-150}{10-0}\\ m=75$

Now, the y-intercept is the point where $x=0$ . So, the point $(0,150)$ has $x$ value as 0.

So, the y-intercept is 150.

Equation of a line in slope-intercept form is given as:

$y=mx+b$

Where, $m$ is the slope and $b$ is the y intercept.

Here, $m=75$ and $b=150$ .

Therefore, the equation that represents the above data is given as:

$y=75x+150$

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2 years ago

How might you prove your observations about the slope of a midsegment in part d using algebra and x- and y-coordinates? Briefly

ioda

Answer: I can use variables to represent the coordinates of the vertices for a general triangle ABC. then I can calculate the midpoints of the sides in terms of the same variables, and calculate the slope of each midsegment showing that the expression for the slope of a midsegment is the same as the expression for the slope of the third side of the triangle proves that the two are parallel.

Step-by-step explanation: this is word for word btw!

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