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Wittaler [7]
1 year ago
14

What is the length of line segment EF if DE is 6ft and DF is 11ft and angle FDE is 40 degrees​

Mathematics
1 answer:
Anna [14]1 year ago
6 0

Answer:

The length of EF = 7.48 feet

Step-by-step explanation:

* Lets consider these tree segment formed triangle DEF

- We have the length of two sides and the measure of the

  including angle between these two sides

* So we can use the cos Rule to find the length of the third side

- The cos rule ⇒ a² = b² + c² - 2bc cosA

# a is the side opposite to angle A

# b is the side opposite to angle B

# c is the side opposite to angle C

# Angle A is the including angle between b and c

* In the problem

∵ DE = 6 feet

∵ DF = 11 feet

∵ m∠FDE = 40° ⇒ including angle between DE and DF

  and opposite to EF

- By using cos Rule

∴ (EF)² = (DE)² + (DF)² - 2(DE)(DF) cos∠FDE

∴ (EF)² = (6)² + (11)² - 2(6)(11) cos(40)

∴ (EF)² = 55.882133 ⇒ take square root for both sides

∴ EF = 7.47543 ≅ 7.48 feet

* The length of EF = 7.48 feet

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Answer:

A quadratic equation is of the form: ax^2+bx+c= 0 .....[1] where

a. b and c are coefficient and x is the variable.

The solutions of the equation are;

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

Given the function: f(x) = 6x^2+12x-7

To find the zero of this function.

Set f(x) = 0

⇒6x^2+12x-7=0

On comparing this with equation [1] we have;

a = 6, b = 12 and c = -7

then;

x = \frac{-12\pm\sqrt{(12)^2-4(6)(-7)}}{2(6)}

x = \frac{-12\pm\sqrt{144+168}}{12}

or

x = \frac{-12\pm\sqrt{312}}{12}

or

x = \frac{-12\pm 2\sqrt{78}}{12}

x = \frac{-6\pm \sqrt{78}}{6}

Therefore, the zeros of the quadratic function f(x) are;

\frac{-6+\sqrt{78}}{6} and \frac{-6-\sqrt{78}}{6}


8 0
1 year ago
Read 2 more answers
There are 950 students at Hanover High School. The ratio of the number of freshmen to all students is 3:10. The ratio of the num
ss7ja [257]

Answer:

Step-by-step explanation:

There are 950 students at Hanover High School. The ratio of the number of freshmen to all students is 3:10. This means that the number of freshmen is 3/10 × total number of students.

Number of freshmen = 3/10×950 =285 freshmen

The ratio of the number of sophomore to all students is 1:2. This means that the number of sophomore is 1/2 × total number of students.

Number of sophomore = 1/2×950 =475 sophomore

The ratio of the number of freshmen to sophomore is the number of freshmen/ the number of

sophomore.

It becomes 285/475 = 57/95

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Answer:

Step-by-step explanation:

The constant term of x^2 + 13x – 48 factors into either (3)(-16) or (-3)(16).

Note how 16 - 3 = 13, which is the coefficient of the middle term.  Thus, the factors are

(x + 16)(x - 3) which is equivalent to x^2 + 16x - 3x - 48, or x^2 + 13x - 48.

8 0
1 year ago
Simplify 5 square root of 11 end root minus 12 square root of 11 end root minus 2 square root of 11 . (1 point)
Feliz [49]

Answer:-9√(11)

Step-by-step explanation:

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Since they are all alike,as in they possess √(11),we can just add or subtract them through

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A boy had 3 apples and gained one. How many apples does he have now? ​
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