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Lapatulllka [165]
2 years ago
9

During normal operation, an electrical component experiences a constant rate of ohmic dissipation ini g = 0.01 W that causes the

conversion of electrical to thermal energy. The component has conductivity k = 10 W/m-K, density r = 1000 kg/m3 , and specific heat capacity c = 100 J/kg-K. The surface of the component is cooled by convection with air at T[infinity] = 20ºC and heat transfer coefficient h = 10 W/m2 -K. The volume of the component is V = 1x10-7 m3 and its surface area is As = 1x10-5 m2.
a. Is a lumped capacitance model of the component appropriate? Justify your answer
b. Assume that your answer to (a) is yes. What is the steady-state temperature of the 0m component?
c. Assume that your answer to (a) is yes. What is the lumped capacitance time constant of the component? At time t - 0, the power to the circuit is shut off and the ohmic dissipation in the component decays to zero according to where τ 6-25 s is the electrical time constant of the circuit.
d. Sketch the temperature of the component as a function of time after the circuit is shut off Be sure to indicate where the temperature starts, where it ends up, and approximately how long it takes to get there.
e. Derive the ordinary differential equation for this problem.
f. What is the initial condition for this problem?

Engineering
1 answer:
Llana [10]2 years ago
4 0

Answer:

Check the explanation

Explanation:

Kindly check the attached image below for the step by step explanation to your answer.

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egoroff_w [7]
D. made because made is a synonym for assembled
4 0
2 years ago
Read 2 more answers
1. Add:<br>(i) 5xy, -2xy, -11xy, 8xy<br>(iv) 3a - 2b + c, 5a + 8b -70​
Cerrena [4.2K]

Answer:

(i) 0

(iv) 8a+6b+c-70

Explanation:

Hope this helps you

8 0
1 year ago
During normal operation, an electrical component experiences a constant rate of ohmic dissipation ini g = 0.01 W that causes the
Llana [10]

Answer:

Check the explanation

Explanation:

Kindly check the attached image below for the step by step explanation to your answer.

4 0
2 years ago
If water molecules pass through a membrane with a steady state flux of 220 mole/(m2 day), how long will it take, in hours, for 0
goblinko [34]

Answer:

<em>0.0386 hr</em>

<em></em>

Explanation:

Area = 565 cm^2 = 0.0565 m^2  (1 cm^2 = 0.0001 m^2)

flux state rate = 220 mole/m^2-day

<em>There are 24 hrs in a day,</em> therefore rate in hrs will be

220/24 = 9.17 mole/m^2-hr

mass of water = 0.4 kg

molar mass of water = (1 x 2) + 16 = 18 kg/mole

therefore,

<em>mole of water = mass of water/molar mass of water</em>

mole of water = 0.4/18 = 0.02 mole

<em>mole flux = mole/area</em> = 0.02/0.0565 = 0.354 mol/m^2

<em>time that will be taken will be for water to pass = mole flux/mole flux rate</em>

time = 0.354/9.17 = <em>0.0386 hr</em>

7 0
2 years ago
A conical enlargement in a vertical pipeline is 5 ft long and enlarges the pipe diameter from 12 in. to 24 in. diameter. Calcula
makkiz [27]

Answer:

F_y = 151319.01N = 15.132 KN

Explanation:

From the linear momentum equation theory, since flow is steady, the y components would be;

-V1•ρ1•V1•A1 + V2•ρ2•V2•A2 = P1•A1 - P2•A2 - F_y

We are given;

Length; L = 5ft = 1.52.

Initial diameter;d1 = 12in = 0.3m

Exit diameter; d2 = 24 in = 0.6m

Volume flow rate of water; Q2 = 10 ft³/s = 0.28 m³/s

Initial pressure;p1 = 30 psi = 206843 pa

Thus,

initial Area;A1 = π•d1²/4 = π•0.3²/4 = 0.07 m²

Exit area;A2 = π•d2²/4 = π•0.6²/4 = 0.28m²

Now, we know that volume flow rate of water is given by; Q = A•V

Thus,

At exit, Q2 = A2•V2

So, 0.28 = 0.28•V2

So,V2 = 1 m/s

When flow is incompressible, we often say that ;

Initial mass flow rate = exit mass flow rate.

Thus,

ρ1 = ρ2 = 1000 kg/m³

Density of water is 1000 kg/m³

And A1•V1 = A2•V2

So, V1 = A2•V2/A1

So, V1 = 0.28 x 1/0.07

V1 = 4 m/s

So, from initial equation of y components;

-V1•ρ1•V1•A1 + V2•ρ2•V2•A2 = P1•A1 - P2•A2 - F_y

Where F_y is vertical force of enlargement pressure and P2 = 0

Thus, making F_y the subject;

F_y = P1•A1 + V1•ρ1•V1•A1 - V2•ρ2•V2•A2

Plugging in the relevant values to get;

F_y = (206843 x 0.07) + (1² x 1000 x 0.07) - (4² x 1000 x 0.28)

F_y = 151319.01N = 15.132 KN

6 0
2 years ago
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