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Tems11 [23]
2 years ago
10

It is advertised that the average braking distance for a small car traveling at 65 miles per hour equals 120 feet. A transportat

ion researcher wants to determine if the statement made in the advertisement is false. She randomly test drives 36 small cars at 65 miles per hour and records the braking distance. The sample average braking distance is computed as 114 feet. Assume that the population standard deviation is 22 feet.
Mathematics
1 answer:
olga nikolaevna [1]2 years ago
5 0

Answer:

We conclude that the average braking distance for a small car traveling at 65 miles per hour equals 120 feet which means that the statement made in the advertisement is correct.

Step-by-step explanation:

We are given that it is advertised that the average braking distance for a small car traveling at 65 miles per hour equals 120 feet. A transportation researcher wants to determine if the statement made in the advertisement is false.

She randomly test drives 36 small cars at 65 miles per hour and records the braking distance. The sample average braking distance is computed as 114 feet. Assume that the population standard deviation is 22 feet.

<em>Let </em>\mu<em> = average braking distance for a small car traveling at 65 miles per hour.</em>

So, Null Hypothesis, H_0 : \mu = 120 feet     {means that the average braking distance for a small car traveling at 65 miles per hour equals 120 feet}

Alternate Hypothesis, H_A : \mu\neq 120 feet     {means that the average braking distance for a small car traveling at 65 miles per hour is different from 120 feet}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                        T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample average braking distance = 114 feet

            \sigma = population standard deviation = 22 feet

            n = sample of small cars = 36

So, <u><em>test statistics</em></u>  =  \frac{114-120}{\frac{22}{\sqrt{36} } }  

                               =  -1.64

The value of z test statistics is -1.64.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

<em>Since our test statistics lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><u><em>we fail to reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that the average braking distance for a small car traveling at 65 miles per hour equals 120 feet which means that the statement made in the advertisement is correct.

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The center of a circle is at the origin on a coordinate grid. The vertex of a parabola that opens upward is at (0, 9). If the ci
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Answer:

"The maximum number of solutions is one."

Step-by-step explanation:

Hopefully the drawing helps visualize the problem.

The circle has a radius of 9 because the vertex is 9 units above the center of the circle.

The circle the parabola intersect only once and cannot intercept more than once.  

The solution is "The maximum number of solutions is one."

Let's see if we can find an algebraic way:

The equation for the circle given as we know from the problem without further analysis is so far x^2+y^2=r^2.

The equation for the parabola without further analysis is y=ax^2+9.

We are going to plug ax^2+9 into x^2+y^2=r^2 for y.

x^2+y^2=r^2

x^2+(ax^2+9)^2=r^2

To expand (ax^2+9)^2, I'm going to use the following formula:

(u+v)^2=u^2+2uv+v^2.

(ax^2+9)^2=a^2x^4+18ax^2+81.

x^2+y^2=r^2

x^2+(ax^2+9)^2=r^2

x^2+a^2x^4+18ax^2+81=r^2

So this is a quadratic in terms of x^2

Let's put everything to one side.

Subtract r^2 on both sides.

x^2+a^2x^4+18ax^2+81-r^2=0

Reorder in standard form in terms of x:

a^2x^4+(18a+1)x^2+(81-r^2)=0

The discriminant of the left hand side will tell us how many solutions we will have to the equation in terms of x^2.

The discriminant is B^2-4AC.

If you compare our equation to Au^2+Bu+C, you should determine A=a^2

B=(18a+1)

C=(81-r^2)

The discriminant is

B^2-4AC

(18a+1)^2-4(a^2)(81-r^2)

Multiply the (18a+1)^2 out using the formula I mentioned earlier which was:

(u+v)^2=u^2+2uv+v^2

(324a^2+36a+1)-4a^2(81-r^2)

Distribute the 4a^2 to the terms in the ( ) next to it:

324a^2+36a+1-324a^2+4a^2r^2

36a+1+4a^2r^2

We know that a>0 because the parabola is open up.

We know that r>0 because in order it to be a circle a radius has to exist.

So our discriminat is positive which means we have two solutions for x^2.

But how many do we have for just x.

We have to go further to see.

So the quadratic formula is:

\frac{-B \pm \sqrt{B^2-4AC}}{2A}

We already have B^2-4AC}

\frac{-(18a+1) \pm \sqrt{36a+1+4a^2r^2}}{2a^2}

This is t he solution for x^2.

To find x we must square root both sides.

x=\pm \sqrt{\frac{-(18a+1) \pm \sqrt{36a+1+4a^2r^2}}{2a^2}}

So there is only that one real solution (it actually includes 2 because of the plus or minus outside) here for x since the other one is square root of a negative number.

That is,

x=\pm \sqrt{\frac{-(18a+1) \pm \sqrt{36a+1+4a^2r^2}}{2a^2}}

means you have:

x=\pm \sqrt{\frac{-(18a+1)+\sqrt{36a+1+4a^2r^2}}{2a^2}}

or

x=\pm \sqrt{\frac{-(18a+1)-\sqrt{36a+1+4a^2r^2}}{2a^2}}.

The second one is definitely includes a negative result in the square root.

18a+1 is positive since a is positive so -(18a+1) is negative

2a^2 is positive (a is not 0).

So you have (negative number-positive number)/positive which is a negative since the top is negative and you are dividing by a positive.

We have confirmed are max of one solution algebraically. (It is definitely not 3 solutions.)

If r=9, then there is one solution.

If r>9, then there is two solutions as this shows:

x=\pm \sqrt{\frac{-(18a+1)+\sqrt{36a+1+4a^2r^2}}{2a^2}}

r=9 since our circle intersects the parabola at (0,9).

Also if (0,9) is intersection, then

0^2+9^2=r^2 which implies r=9.

Plugging in 9 for r we get:

x=\pm \sqrt{\frac{-(18a+1)+\sqrt{36a+1+4a^2(9)^2}}{2a^2}}

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x=\pm \sqrt{\frac{-(18a+1)+\sqrt{(18a+1)^2}}{2a^2}}

x=\pm \sqrt{\frac{-(18a+1)+18a+1}{2a^2}}

x=\pm \sqrt{\frac{0}{2a^2}}

x=\pm 0

x=0

The equations intersect at x=0. Plugging into y=ax^2+9 we do get y=a(0)^2+9=9.  

After this confirmation it would be interesting to see what happens with assume algebraically the solution should be (0,9).

This means we should have got x=0.

0=\frac{-(18a+1)+\sqrt{36a+1+4a^2r^2}}{2a^2}

A fraction is only 0 when it's top is 0.

0=-(18a+1)+\sqrt{36a+1+4a^2r^2}

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18a+1=\sqrt{36a+1+4a^2r^2

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Square root both sides:

9=r

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Let's go through the radius choices.

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2 years ago
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Answer:

II. This finding is significant for a two-tailed test at .01.

III. This finding is significant for a one-tailed test at .01.

d. II and III only

Step-by-step explanation:

1) Data given and notation    

\bar X=19.2 represent the battery life sample mean    

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p_v represent the p value for the test (variable of interest)    

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We need to conduct a hypothesis in order to check if the mean battery life is equal to 18 or not for parta I and II:    

Null hypothesis:\mu = 18    

Alternative hypothesis:\mu \neq 18    

And for part III we have a one tailed test with the following hypothesis:

Null hypothesis:\mu \leq 18    

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Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

3) Calculate the statistic    

We can replace in formula (1) the info given like this:    

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Answer:

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Step-by-step explanation:

* Lets talk about the simple interest

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# A = Total amount (principal + interest)

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# r = Rate of Interest per year in decimal r = R/100

# R = Rate of Interest per year as a percent R = r * 100

# t = Time period involved in months or years

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* lets solve the problem

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∴ P = $12,000

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∵ I = Prt

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∵ I = A - P

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- The amount of interest after 3 years is 2340

- Lets find the amount of interest in the two years

∴ I = 7000(r × 2) = 14000r

- The amount of interest after the 3 years is the sum of the interest in

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∴ r = 2340 ÷ 26000 = 0.09

∵ The rate R in percentage = r × 100

∴ R = 0.09 × 100 = 9%

∴ The rate of simple interest is 9%

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