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marishachu [46]
2 years ago
7

A container of gas is heated from 250 K to 303 K. What is the new pressure if the initial pressure is 880 kPa? (Assume constant

volume).
Chemistry
1 answer:
evablogger [386]2 years ago
5 0

Answer:

The new pressure at constant volume is 1066.56 kPa

Explanation:

Assuming constant volume, the pressure is diectly proportional to the temperature of a gas.

Mathematically, P1/T1 = P2 /T2

P1 = 880 kPA= 880 *10^3 Pa

T1 = 250 K

T2 = 303 K

P2 =?

Substituting for P2

P2 = P1 T2/ T1

P2 = 880 kPa * 303 / 250

P2 = 266,640 kPa/ 250

P2 = 1066.56 kPa.

The new pressure of the gas is 1066.56 kPa

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An atom has four electrons in its valence shell. What types of covalent bonds is it capable of forming?
Ierofanga [76]

Answer:

The answer to your question is below

Explanation:

An atom with four electrons in its valence shell is capable of forming:

single bonds and atom with the described characteristics, can form 4 single bonds or a combination of single bonds and double or triple bonds. Ex alkanes

double bonds this atom can form one double bond and two single bonds or two double bonds. Ex alkenes

triple bonds this atom can form one triple bond and one single bond, Ex alkynes.

6 0
2 years ago
The seven most abundant ions in seawater make up more than 99% by mass of the dissolved compounds. Here are their abundances in
zhannawk [14.2K]

Answer:

Here's what I get  

Explanation:

(a) Mass % of each ion

\text{Mass \%} = \dfrac{\text{mass}}{\text{total mass}} \times 100 \, \%\\\\= \dfrac{\text{mass}}{34 380} \times 100 \, \%\\= 2.903 \times 10^{-3} \times\text{"mass"} \, \%

I used this template to calculate the percentages in the table below.

<u>            Ion               Abundance                                   Mass %                </u>

Na⁺                     10 560                                   30.72

K⁺                       <u>     380              </u>                     <u>   1.11                  </u>

Alkali metals                    10 940                                     31.82

Mg²⁺                     1 270                                      3.69

Ca²⁺                        <u>400             </u>                     <u>    1.16                  </u>

Alkaline earth metals        <u>1 670              </u>                        <u> 4.86                </u>

Total metal ions                            12 610                                      36.68

Cl⁻                     18 980                                     55.20

SO₄²⁻                  2 650                                       7.71

HCO₃⁻                   140                                        0.41

Anions                                          <u>21 770 </u>                                    <u>  63.32 </u>

TOTAL                                         34 380                                     100.00

(b) 30.72 % of the total mass is sodium ion.

(c) Alkaline earth metals vs alkali metals

\dfrac{\text{alkaline earth}}{\text{alkali}} = \dfrac{4.86}{31.82} = \dfrac{1 }{6.55}

The mass percent of alkali metal ions is 6.55 times that of alkaline earth metal ions.

(d) The mass of anions is greater than that of cations.

7 0
2 years ago
Two sets of flasks are connected by a hollow copper pipe, as shown. Which set will change the temperature most quickly?
Dennis_Churaev [7]
Hmm. I'm not 100% sure but. I'm pretty sure it's A because the heated water is below and there's a hotter temp. Also because it's copper, heat will move more quickly. I'm not 100% sure, are there notes you can check?
8 0
2 years ago
Read 2 more answers
A blacksmith making a tool heats 525 grams of steel to 1230°C. After hammering the steel, she places it into a bucket of water t
Simora [160]
C
WELL HOPE THIS CAN HELP U
6 0
2 years ago
A 25.0 g sample of an alloy was heated to 100.0 oC and dropped into a beaker containing 90 grams of water at 25.32 oC. The tempe
elena55 [62]

Answer:

The specific heat of the alloy C_{a} = 0.37 \frac{KJ}{Kg K}

Explanation:

Mass of an alloy m_{a} = 25 gm

Initial temperature T_{a} = 100°c = 373 K

Mass of water m_{w} = 90 gm

Initial temperature of water T_{w} = 25.32 °c = 298.32 K

Final temperature T_{f} = 27.18 °c = 300.18 K

From energy balance equation

Heat lost by alloy = Heat gain by water

m_{a} C_{a}  [T_{a} - T_{f}] = m_{w} C_w (T_{f} -T_{w} )

25 × C_{a} × ( 373 - 300.18 ) = 90 × 4.2 (300.18 - 298.32)

C_{a} = 0.37 \frac{KJ}{Kg K}

This is the specific heat of the alloy.

4 0
2 years ago
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