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Lena [83]
2 years ago
11

John was a high school teacher earning $ 80,000 per year. He quit his job to start his own business in pizza catering. In order

to learn how to run the pizza catering business, John enrolled in a TAFE to acquire catering skills. John’s course was for 3 months. John had to pay $2,000 as tuition for the 3 months.
After the training, John withdrew $110,000 from his savings account. He had been earning 5 percent interest per year for this account. He also borrowed $50,000.00 from his friend whom he pays 6 percent interest per year. Further, to start the business John used his own premises. He was receiving $12,000 from rent per year. Finally, to start the business John uses $50,000 he had been given by his father to go on holiday to USA.

John’s first year of business can be summarised as follows:

Item Amount $
Revenue- Pizza Section 400,000
Revenue- Beverages Section 190,000
2 Cashiers (wages per worker) 55,000
Pizza ingredients 50,000
Manager 75,000
3 Pizza bakers (wages per baker) 60,000
Equipment 10,000

Based on your calculated accounting profit and economic profit, would you advise John to return to his teaching job? Show your work (10 marks)
 
Engineering
1 answer:
Anton [14]2 years ago
4 0

Answer:

John should continue with his catering business because accounting and economic profits from pizza catering are more than his annual salary from teaching.

Explanation:

John can earn from teaching $80,000 annually

For starting business of pizza catering John will incur following expense

Tuition for catering skills $2,000

Opportunity cost for withdrew of funds ($110,000 * 5%) $5,500

Interest for Borrowing from friend ($50,000 * 6%) $3,000

Opportunity cost of Rent from premises $12,000

Total opportunity cost $22,500

Revenue:

Revenues from Pizza $400,000

Revenue from Beverages $190,000

Total revenue $590,000

Expenses:

Cashier wages ($55,000 * 2) $110,000

Pizza ingredients $50,000

Manager salary $75,000

Pizza bakers wages ($60,000 * 3) $180,000

Equipment $10,000

Total Expense $425,000

Net Income - Accounting Profit ($590,000 - $425,000) = $165,000

Less opportunity cost $22,500

Economic Profit $142,500

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A 10-m long steel linkage is to be designed so that it can transmit 2 kN of force without stretching more than 5 mm nor having a
Fed [463]

Answer:

<em>minimum required diameter of the steel linkage is 3.57 mm</em>

<em></em>

Explanation:

original length of linkage l = 10 m

force to be transmitted  f = 2 kN = 2000 N

extension e = 5 mm= 0.005 m

maximum stress σ = 200 N/mm^2 = 2*10^{8}  N/m^{2}

maximum stress allowed on material σ = force/area

imputing values,

200 = 2000/area

area = 2000/(2*10^{8}) = 10^{-5} m^2

recall that area = \pi d^{2} /4

10^{-5} = \frac{3.142*d^{2} }{4} = 0.7855d^{2}

d^{2} = \frac{10^{-5} }{0.7855} = 1.273*10^{-5}

d = \sqrt{1.273*10^{-5}  } = 3.57*10^{-3} m = 3.57 mm

<em>maximum diameter of  the steel linkage d = 3.57 mm</em>

4 0
2 years ago
A 60-kg woman holds a 9-kg package as she stands within an elevator which briefly accelerates upward at a rate of g/4. Determine
Anuta_ua [19.1K]

Answer:

force R = 846.11 N

lifting force L = 110.36 N

if cable fail complete both R and L will be zero

Explanation:

given data

mass woman mw = 60 kg

mass package mp = 9 kg

accelerates rate a = g/4

to find out

force R and lifting force L and if cable fail than what values would R and L acquire

solution

we calculate here first reaction R force

we know elevator which accelerates upward

so now by direction of motion , balance the force that is express as

R - ( mw + mp ) × g = ( mw + mp ) × a

here put all these value and a = g/4 and use g = 9.81 m/s²

R - ( 60 + 9 ) × 9.81 = ( 60 + 9  ) × g/4

R = ( 69  ) × 9.81/4  + ( 69 ) 9.81

R = 69  ( 9.81 + 2.4525 )

force R = 846.11 N

and

lifting force is express as here

lifting force = mp ( g + a)

put here value

lifting force = 9 ( 9.81 + 9.81/4)

lifting force L = 110.36 N

and

we know if cable completely fail than body move free fall and experience no force

so both R and L will be zero

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2 years ago
An electric field is expressed in rectangular coordinates by E = 6x2ax + 6y ay +4az V/m.Find:a) VMN if point M and N are specifi
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Answer:

a.) -147V

b.) -120V

c.) 51V

Explanation:

a.) Equation for potential difference is the integral of the electrical field from a to b for the voltage V_ba = V(b)-V(a).

b.) The problem becomes easier to solve if you draw out the circuit. Since potential at Q is 0, then Q is at ground. So voltage across V_MQ is the same as potential at V_M.

c.) Same process as part b. Draw out the circuit and you'll see that the potential a point V_N is the same as the voltage across V_NP added with the 2V from the other box.

Honestly, these things take practice to get used to. It's really hard to explain this.

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2 years ago
It is said that Archimedes discovered his principle during a bath while thinking about how he could determine if King Hiero’s cr
arlik [135]

Answer: The crown is not made of pure gold.

Explanation:

Archimedes discovered that any solid, of any shape, when submerged in a liquid receives an upward force, equal to the weight of the volume of the liquid removed by the solid, which is equal to the solid volume.

So, if any body is weighed in air, the normal force will be equal to the gravity force (which we call weight) which can be expressed as follows:

Fg = m g = δ V g = 34.7 N

When submerged in water, the normal force is equal to the difference between the actual weight, and the upward force due to Archimedes' principle, called buoyant force, as follows:

Fn = Fg - Ep = δx. V. g - δH20 . V. g = 31.5 N

Dividing Fg between Fn, and simplifying common terms, we have:

δx / (δx - δh20) = 34.7 / 31.5 = 1.10

Solving for δx, we get the following value:

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