Question

A particle has an initial velocity of v0 = 14 ft/s to the right, at s0 = 0, and a = 2 ft/s2 to the left. determine its position t=10 s.

Answer 1

Answer:

The particle is 40 m to the right of its initial position.

Explanation:

Given data

• Initial velocity (v₀): 14 ft/s (in direction to the positive x-axis)

• Initial position (s₀): 0 m

• Acceleration (a): -2 ft/s² (in direction to the negative x-axis)

We can determine the position of the particle at a time t = 10 s, using the following kinematic expression.

s = s₀ + v₀.t + 1/2.a.t²

s(10) = 0 m + 14 ft/s × 10 s + 1/2 × (-2 ft/s²) × (10 s)²

s = 40 m

The particle is 40 m to the right of its initial position.