Shania's test scores in 8 subjects were 88, 91, 85, 74, 69, 72, 80, and 87. Which measure should Shania use to find how much the
1 answer:
Answer with explanation:
Test Scores of Shania's in 8 subject are: 88, 91, 85, 74, 69, 72, 80, and 87.
To calculate mean we add all the variate and divide by total number of Variate in the data set.
So, Mean of the Data set
To calculate , how much the scores on her tests vary, on average, from the mean score
We will Calculate mean absolute Deviation.
To calculate it,we will find absolute difference of each variate from mean.
| 88 - 80.75|=7.25
|91-80.75|=10.25
|85 -80.75|=4.25
|74-80.75|=6.75
......
........
Then Shania should calculate mean of the new data set obtained,which is absolute difference of each variate from mean.
→The Measure that,Shania should use to find how much the scores on her tests vary, on average, from the mean score is:
Mean absolute deviation
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Answer:
a) P=0
b) P=0.164
c) P=0.145
Step-by-step explanation:
We have 12 pieces, with 3 of each of the 4 flavors.
You draw the first 4 pieces.
a) The probability of getting all of the same flavor is 0, because there are only 3 pieces of each flavor. Once you get the 3 of the same flavor, there are only the other flavors remaining.
b) The probability of all 4 being from different flavor can be calculated as the multiplication of 4 probabilities.
The first probability is for the first draw, and has a value of 1, as any flavor will be ok.
The second probability corresponds to drawing the second candy and getting a different flavor. There are 2 pieces of the flavor from draw 1, and 9 from the other flavors, so this probability is 9/(9+2)=9/11≈0.82.
The third probability is getting in the third draw a different flavor from the previos two draws. We have left 10 candys and 4 are from the flavor we already picked. Then the third probabilty is 6/10=0.6.
The fourth probability is getting the last flavor. There are 9 candies left and only 3 are of the flavor that hasn't been picked yet. Then, the probability is 3/9=0.33.
Then, the probabilty of picking the 4 from different flavors is:
c) We can repeat the method for the previous probabilty.
The first draw has a probability of 1 because any flavor is ok.
In the second draw, we may get the same flavor, with probability 2/11, or we can get a second flavor with probability 9/11. These two branches are ok.
For the third draw, if we have gotten 2 of the same flavor (P=2/11), we have to get a different flavor (we can not have 3 of the same flavor). This happen with probability 9/10.
If we have gotten two diffente flavors, there are left 4 candies of the picked flavors in the remaining 10 candies, so we have a probabilty of 4/10.
For the fourth draw, independently of the three draws, there are only 2 candies left that satisfy the condition, so we have a probability of 2/9.
For the first path, where we pick 2 candies of the same flavor first and 2 candies of the same flavor last, we have two versions, one for each flavor, so we multiply this probability by a factor of 2.
We have then the probabilty as:
The first thing we must do for this case is to find the equation of the line.
We have then:
We choose an ordered pair:
Substituting values:
From here we conclude:
Intersection with y:
We evaluate x = 0 in the function:
Slope of the line:
Point (-2, -5):
We evaluate the value of x = -2 and the value of y = -5
The equation is satisfied.
Point (8, 0):
It is part of the table, therefore belongs to the line.
Answer:
The slope is 1/2
The y-intercept is -4.
The points (-2, -5) and (8, 0) are also on the line.
We have then:
We choose an ordered pair:
Substituting values:
From here we conclude:
Intersection with y:
We evaluate x = 0 in the function:
Slope of the line:
Point (-2, -5):
We evaluate the value of x = -2 and the value of y = -5
The equation is satisfied.
Point (8, 0):
It is part of the table, therefore belongs to the line.
Answer:
The slope is 1/2
The y-intercept is -4.
The points (-2, -5) and (8, 0) are also on the line.