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lubasha [3.4K]
2 years ago
14

What is the volume of a cylindrical bucket that is 35 cm tall and has a base with a diameter of 21 cm? Use Pi = StartFraction 22

Over 7 EndFraction and round your answer to the nearest tenth of a cubic centimeter.
Mathematics
2 answers:
Naya [18.7K]2 years ago
8 0

Answer:

The volume of the cylindrical bucket to the nearest tenth of a cubic centimeter is 12,122.6 cm^3

Step-by-step explanation:

In this question, we are asked to calculate the volume of a cylindrical bucket with height 35cm and a base diameter of 21cm

Mathematically, the volume of the cylinder V can be calculated using the formula;

V = π * r^2 * h

The value of π = 22/7

since D = 21cm, r = D/2 = 21/2 = 10.5cm

Substituting these values, we have

V = 22/7 * 10.5^2 * 35 = 12,122.621

To the nearest tenth of a cubic centimeter is 12,122.6 cm^3

Valentin [98]2 years ago
4 0

Answer:

12127.5

Step-by-step explanation:

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Find each measure for the given set of data: 11, 13, 17, 20, 22, 25, 27, 31, 31, 33, Mean= Median= Range= interquartile range= I
Tresset [83]

Answer:

Mean=23

Median =23.5

Range=22

Interquartile range = 14

Step-by-step explanation:

Given set of data

11,13,17,20,22,25,27,31,31,33

Mean =\frac{11+13+17+20+22+25+27+31+31+33}{10}

          =\frac{230}{10}

          =23

The(\frac{n}{2}) th term= the 5th term

                        =22

The  (\frac{n}{2}+1)^{th} term = The 6^{th term

                               = 25

The median = \frac{22+25}{2}

                   =23.5

Range = Highest term - lowest term

           =33- 11

            =22

Here lower half {11,13,17,20,22}

The middle number of lower half is first quartile.

Q₁ = 17

And lower half is{25,27,31,31,33}

The middle number of upper half is third quartile.

Q₃=31

Interquartile Range =Q₃-Q₁

                                =31-17

                                 =14

8 0
2 years ago
Find the percent of change from 688 qt to 172 qt.
Alekssandra [29.7K]

There is 75% decrease.

Step-by-step explanation:

Given,

Old value = 688 qt

New value = 172 qt

Change = New value - Old value

Change = 172 - 688

Change = -516 qt

The negative sign indicates decrease.

Decrease percent = \frac{Change}{Old\ value}*100

Decrease percent = \frac{516}{688}*100

Decrease percent = \frac{51600}{688}

Decrease percent = 75%

There is 75% decrease.

Keywords: division, subtraction

Learn more about subtraction at:

  • brainly.com/question/10196212
  • brainly.com/question/1021953

#LearnwithBrainly

3 0
2 years ago
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Which quadratic equation is equivalent to (x – 4)2 – (x – 4) – 6 = 0?
Viktor [21]

I hope choices must be given in the problem.

I am showing the method to find the equivalent equation of the above equation. You can match with your given choices.

First step is to expand the first term. So,

(x-4)² = (x - 4)(x - 4) Since a²= a*a

= x² - 4x - 4x + 4 * 4 By multiplying.

= x² -8x + 16 Combine the like terms.

So, (x - 4)² - (x -4) - 6

= x² - 8x + 16 - x + 4 - 6

= x² - 9x + 14 Combine the like terms.

So, equivalent equation of the above equation is x² - 9x + 14 = 0.

5 0
2 years ago
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On a coordinate plane, 2 exponential fuctions are shown. Function f (x) decreases from quadrant 2 into quadrant 1 and approaches
Gala2k [10]

Answer:

g(x)=6(3)^x

Step-by-step explanation:

We are given  that

f(x)=6(\frac{1}{3})^x

Function f decreases from quadrant  2 to quadrant 1 and approaches  y=0

It cut the y- axis at (0,6) and passing through the point (1,2).

Function g(x) approaches y=0 in quadrant 2 and increases into quadrant 1.

It passing through the point (-1,2) and cut the y-axis at point (0,6).

Reflection across y- axis:

Rule of transformation is given by

(x,y)\rightarrow (-x,y)

Using the rule then we get

g(x)=6(\frac{1}{3})^{-x}=6(3)^x

By using

x^{-a}=\frac{1}{x^a}

Substitute x=-1

g(-1)=6\times (\frac{1}{3})=2

Substitute x=0

g(0)=6

Therefore,g(x)=6(3)^x is true.

8 0
2 years ago
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Julia went into a movie theater and bought 2 bags of popcorn and 5 pretzels, costing
andreyandreev [35.5K]

Answer:

A bag of pop corn costs $8, and each Pretzel costs $4.25.

Step-by-step explanation:

Let b be the price of popcorn, and p the price of Pretzels. If the girl bought 2 bags of popcorn and 5 Pretzels and it cost her $37.25, we have the equation

2b+5p=37.25  <em>(this says that the cost of 2 popcorn bags plus 5 pretzels equals $37.25)</em> .

And, since Zoe bought 8 popcorn bags and 9 Pretzels with a total price of $102.25, we get the equation

8b+9p=102.25<em> (this says that the cost of 8 popcorn bags plus 9 Pretzels equals $102.25).</em>

Thus, we have two equations

1. 2b+5p=37.25

2. 8b+9p=102.25

and we solve them by first multiplying equation (1) by 4:

4(2b+5p=37.25 )\rightarrow (8b+20p=149),

and then subtracting it from equation (2):

\:\:\:\:\: 8b+9p=102.25\\-(8b+20p=149)\\\line(1,0){3 cm}\\-11p=-46.75\\\\\boxed{p=\$4.25}

Now we put this value of p into equation (1) and get:

2b+5(4.25)=37.25

and we solve for b to get:

2b=37.25-21.5

\boxed{ b=8}

Therefore, a bag of popcorn costs $8, and each Pretzel costs $4.25.

8 0
2 years ago
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