Question

He half-life of gold-194 is approximately 1.6 1.6 days. Step 1 of 3 : Determine a so that A(t)=A0at A ( t ) = A 0 a t describes the amount of gold-194 left after t days, where A0 A 0 is the amount at time t=0 t = 0 . Round to six decimal places.

Answer 1

Answer: A(t) = Ao × e^-kt

Step-by-step explanation:

A(t) = Ao × e^-kt

Where

A(t) = Amount of gold left after time 't'

t = Amount of time passed

Ao = Initial amount of gold at t=0

k = constant.

No value given